tim x
x+1/2=8/x+1
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Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
x(x - 1)(x - 1) = (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = (x - 2)xx(x - 1) - (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = 0
<=> x2(x - 1) = 0
<=> x = 0
<=> x - 1 = 0
x = 0 + 1
x = 1
=> x = 0 hoặc 1
`x xx 6/7=5/14`
`=>x=5/14:6/7`
`=>x=5/14xx7/6`
`=>x=35/84`
`=>x=5/12`
Vậy `x=5/12`
__
`x:2/3=4/9`
`=>x=4/9xx2/3`
`=>x=8/27`
Vậy `x=8/27`
__
`x-1/4=3/2`
`=>x=3/2+1/4`
`=>x=6/4+1/4`
`=>x=7/4`
Vậy `x=7/4`
__
`x+4/5=8/9`
`=>x=8/9-4/5`
`=>x=40/45-36/45`
`=>x=4/45`
Vậy `x=4/45`
\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)
\(x\) \(=\dfrac{5}{14}:\dfrac{6}{7}\)
\(x\) \(=\dfrac{5}{12}\)
\(x:\dfrac{2}{3}=\dfrac{4}{9}\)
\(x\) \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)
\(x\) \(=\dfrac{8}{27}\)
\(x-\dfrac{1}{4}=\dfrac{3}{2}\)
\(x\) \(=\dfrac{3}{2}+\dfrac{1}{4}\)
\(x\) \(=\dfrac{7}{4}\)
\(x+\dfrac{4}{5}=\dfrac{8}{9}\)
\(x\) \(=\dfrac{8}{9}-\dfrac{4}{5}\)
\(x\) \(=\dfrac{4}{45}\)
\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\\ \Rightarrow\left(x+1\right)^2\left(x+1\right)=8\cdot8\\ \left(x+1\right)^3=64\\ \left(x+1\right)^3=4^3\\ \Rightarrow x+1=4\\ x=3\)
\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\)
\(\Leftrightarrow\left(x+1\right)^3=64=4^3\)
\(\Leftrightarrow x+4=1\Rightarrow x=3\)
\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=4\) hoặc \(x+1=-4\)
*\(x+1=4\Rightarrow x=3\)
*\(x+1=-4\Rightarrow x=-5\)
Vậy \(\text{x = 3; x = -5}\)
so nhieu cua tu tieng anh: candy