Giúp mk 3 câu c,d,e, xin đấy!!!
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4 Can you tell me the way to the museum?
5 Her family is going to visit Huong in Can Tho this summer
6 How far is it from your house to Quynh coi Primary school?
7 In VN the new school year begins on September the fifth
1: \(\left(x+2y\right)^2=x^2+4xy+4y^2\)
2: \(\left(2x+3y\right)^2=4x^2+12xy+9y^2\)
3: \(\left(3x-2y\right)^2=9x^2-12xy+4y^2\)
\(1,=\left(x-3\right)^2\\ 2,=\left(5+x\right)^2\\ 3,=\left(\dfrac{1}{2}x+2b\right)^2\\ 4,=\left(\dfrac{1}{3}-y^4\right)^2\\ 5,=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\\ 6,=\left(2y-5\right)\left(4y^2+10y+25\right)\\ 7,=\left(a^2-b\right)\left(a^4+a^2b+b^2\right)\\ 8,=\left(x-5\right)^2\\ 9,=8\left(x^3-\dfrac{1}{64}\right)=8\left(x-\dfrac{1}{4}\right)\left(x^2+\dfrac{1}{4}x+\dfrac{1}{16}\right)\)
1 intentively
2 breking
3 preferential
4 deadened
5 refusal
6 exhausted
7 breathed
8 Inadvisable
9 consuming
10 compeled
Không sao đâu bạn . Có gì khó thì cứ đăng lên bọn mình sẽ giải hộ
\(b,\left(1\right)4Al+3O_2\underrightarrow{^{to}}2Al_2O_3\\ \left(2\right)Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\\ \left(3\right)Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow3BaSO_4\downarrow+2AlCl_3\\ \left(4\right)AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\\ \left(5\right)Al\left(NO_3\right)_3+3KOH\rightarrow Al\left(OH\right)_3\downarrow+3KNO_3\\ \left(6\right)2Al\left(OH\right)_3\underrightarrow{^{to}}Al_2O_3+3H_2O\)
\(d,\left(1\right)3Fe+2O_2\underrightarrow{^{to}}Fe_3O_4\\ \left(2\right)Fe_3O_4+4CO\underrightarrow{^{to}}3Fe+4CO_2\\ \left(3\right)FeO+H_2\underrightarrow{^{to}}Fe+H_2O\\ \left(4\right)Fe+4HNO_3\rightarrow Fe\left(NO_3\right)_3+NO+2H_2O\\ \left(5\right)2Fe\left(NO_3\right)_3+Fe\rightarrow3Fe\left(NO_3\right)_2\\ \left(6\right)Fe\left(NO_3\right)_2+2KOH\rightarrow Fe\left(OH\right)_2\downarrow+2KNO_3\\ \left(7\right)4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\)
c: Ta có: \(\sqrt{x+4\sqrt{x-4}}=5\)
\(\Leftrightarrow\sqrt{x-4}+2=5\)
\(\Leftrightarrow\sqrt{x-4}=3\)
\(\Leftrightarrow x-4=9\)
hay x=13
c: Ta có: √x+4√x−4=5x+4x−4=5
⇔√x−4+2=5⇔x−4+2=5
⇔√x−4=3⇔x−4=3
⇔x−4=9⇔x−4=9
hay x=13
Mình ko ghi đề nhé
c) \(\Rightarrow\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}-\frac{2}{5}=-\frac{57}{10}\)
\(\Rightarrow3x-3,7=-\frac{19}{2}=-9,5\)
\(\Rightarrow3x=-5,8\)
\(\Rightarrow x=-\frac{29}{15}\)
d) \(\Rightarrow\left(3\frac{1}{4}-\frac{7}{6}\right).x=\frac{25}{12}\)
\(\Rightarrow\frac{25}{12}.x=\frac{25}{12}\)
\(\Rightarrow x=1\)
e) \(\Rightarrow x\left(\frac{93}{17}-\frac{17}{4}\right)+\frac{22}{7}.\frac{22}{3}=\frac{4}{11}\)
\(\Rightarrow x.\frac{83}{68}+\frac{484}{21}=\frac{4}{11}\)
\(\Rightarrow x.\frac{83}{68}=-\frac{5240}{231}\)
\(\Rightarrow x=...\) (số lẻ lắm)
Những bài này lần sau bạn nên tự làm nhé
cám ơn bn nhiều, lớp 7 á??? ak, cám ơn chị!!!!