Làm tính chia : (x3-x2-7x+3):(x-3)
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x3 – 7x + 3 – x2 = x3 – x2 – 7x + 3
Thực hiện phép chia:
Vậy (x3 – x2 – 7x + 3) : (x – 3) = x2 + 2x – 1
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\(\left(3x-7x+3-2x\right):\left(x-3\right)=\left(3x-2x-7x+3\right):\left(x-3\right)\)
\(\left(3-6x\right):\left(x-3\right)-\left(3-6x\right):\left(x-3\right)=0\)
\(0=0\)
vậy \(x\in\varnothing\)
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a) A = ( x 2 – 6x)B.
b) A = (-x – 8)B + 2
c) A = (x + 3)B + 6.
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Cách 1: Thực hiện phép chia
Vậy (x4 – x3 + x2 + 3x) : (x2 – 2x + 3) = x2 + x
Cách 2: Phân tích x4 – x3 + x2 + 3x thành nhân tử có chứa x2 + x
x4 – x3 + x2 + 3x
= x.(x3 – x2 + x + 3)
= x.(x3 – 2x2 + 3x + x2 – 2x + 3)
= x.[x.(x2 – 2x + 3) + (x2 – 2x + 3)]
= x.(x + 1)(x2 – 2x + 3)
Vậy (x4 – x3 + x2 + 3x) : (x2 – 2x + 3) = x(x + 1)
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\(=\left(x^3-3x^2+2x^2-6x-x+3\right):\left(x-3\right)\\ =\left(x-3\right)\left(x^2+2x-1\right):\left(x-3\right)\\ =x^2+2x-1\)
(x3 - 7x + 3 -x2) : (x-3)
= [(x2 + 2x - 1 ).(x-3)] : (x-3)
= x2 + 2x - 1
mk đoán là vậy
x^3 - x^2 - 7x + 3 x - 3 x^2 + 2x - 1 x^3 - 3x^2 2x^2 - 7x 2x^2 - 6x -x + 3 -x + 3 0
Vậy \(\left(x^3-x^2-7x+3\right):\left(x-3\right)=x^2+2x-1\)