sắp xếp các phân số sau theo thứ tự từ lướn đến bé : 2/3, 3/8, 5/6, 5/12, 3/4
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a: -10/8<-1
-19/19=-1
-1<-2/10<0
0<5/12<1<17/15
=>17/15>1>5/12>-2/10>-19/19>-10/8
b: -1/3=-4/12; -5/12=-5/12; -3/4=-9/12; -1/4=-3/12; -7/12=-7/12
=>-3/4<-7/12<-5/12<-1/3<-1/4
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(1\frac{1}{2};1\frac{1}{3};1\frac{1}{4};1\frac{1}{5};1\frac{1}{6};1\frac{1}{7};1\frac{1}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
Vì \(\frac{1}{2}>\frac{1}{3}>\frac{1}{4}>\frac{1}{5}>\frac{1}{6}>\frac{1}{7}>\frac{1}{8}\)
=> \(1\frac{1}{2}>1\frac{1}{3}>1\frac{1}{4}>1\frac{1}{5}>1\frac{1}{6}>1\frac{1}{7}>1\frac{1}{8}\)
Hay \(\frac{3}{2}>\frac{4}{3}>\frac{5}{4}>\frac{6}{5}>\frac{7}{6}>\frac{8}{7}>\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\) ; \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\) ; \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\)
\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\) ; \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)
⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)
\(\dfrac{1}{2}=\dfrac{1\cdot24}{2\cdot24}=\dfrac{24}{48}\)
\(\dfrac{3}{48}=\dfrac{3\cdot1}{48\cdot1}=\dfrac{3}{48}\)
\(\dfrac{8}{12}=\dfrac{8\cdot4}{12\cdot4}=\dfrac{32}{48}\)
\(\dfrac{5}{6}=\dfrac{5\cdot8}{6\cdot8}=\dfrac{40}{48}\)
\(\dfrac{7}{12}=\dfrac{7\cdot4}{12\cdot4}=\dfrac{28}{48}\)
mà 3<24<28<32<40
nên \(\dfrac{3}{48}< \dfrac{1}{2}< \dfrac{7}{12}< \dfrac{8}{12}< \dfrac{5}{6}\)
Bé đến lớn:
-4;-3;-1;0;2;5;7
Hok tốt!
@Kaito Kid
3/4, 5/6, 2/3, 5/12, 3/8