9.4^2-7.(-2)^3
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\(A=\frac{-3}{5}+\left(\frac{-2}{5}+2\right)\)
\(A=\frac{-3}{5}+\frac{8}{5}\)
\(A=1\)
\(B=\frac{3}{7}+\left(\frac{-1}{5}+\frac{-3}{7}\right)\)
\(B=\frac{3}{7}+\frac{-1}{5}+\frac{-3}{7}\)
\(B=\left(\frac{3}{7}+\frac{-3}{7}\right)+\frac{-1}{5}\)
\(B=0+\frac{-1}{5}\)
\(B=\frac{-1}{5}\)
\(C=\frac{-7}{9}.\frac{4}{11}+\frac{-7}{9}.\frac{7}{11}+\frac{52}{9}\)
\(C=\frac{-7}{9}.\left(\frac{4}{11}+\frac{7}{11}\right)+\frac{52}{9}\)
\(C=\frac{-7}{9}.1+\frac{52}{9}\)
\(C=\frac{-7}{9}+\frac{52}{9}\)
\(C=5\)
\(D=50\%.\frac{4}{3}.10.\frac{7}{35}.0,75\)
\(D=\frac{50}{100}.\frac{4}{3}.10.\frac{7}{35}.\frac{75}{100}\)
\(D=\frac{1}{2}.\frac{4}{3}.10.\frac{1}{5}.\frac{3}{4}\)
\(D=\left(\frac{1}{2}.\frac{1}{5}.10\right).\left(\frac{4}{3}.\frac{3}{4}\right)\)
\(D=1.1\)
\(D=1\)
A= 1
B= -1/5
C=5
D=1
mik có ý kiến lần sau bạn đặt câu hỏi nhớ ghi phân số trên dưới cho dễ nhìn nha
\(C=\dfrac{2^6\cdot3^{10}}{3^9\cdot2^6}=3\\ D=\dfrac{3^{24}\cdot3^{10}}{3^{21}\cdot3^{11}}=\dfrac{3^{34}}{3^{32}}=3^2=9\\ F=\dfrac{2^{45}\cdot5^{14}}{5^{15}\cdot2^{47}}=\dfrac{1}{2^2\cdot5}=\dfrac{1}{20}\\ G=\dfrac{2^2\cdot5^2\cdot5^3}{2^3\cdot5^4}=\dfrac{1\cdot5}{2}=\dfrac{5}{2}\)
C=3
D=9
F=1/20
G=5/2
Em ko giải chi tiết vì nó lâu
Mong thông cảm!
a, -3/4 + 3/7 + -1/4 + 4/9 + 4/7
=(−34+−14)+(37+47)+49(−34+−14)+(37+47)+49
=−1+1+49−1+1+49
=49
\(\frac{2^{10}.3^8-2^8.3^9.4}{2^{10}.3^6.9+2^{10}.3^9}=\frac{2^{10}.\left(3^8-3^9\right)}{2^{10}\left(3^9-3^9\right)}=\frac{3^8-3^9}{3^9-3^9}=\frac{3^8\left(1-3\right)}{3^9\left(1-1\right)}=\frac{3^8.\left(-2\right)}{3^9.0}=0\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^6+2^{16}\cdot3^9}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^6\left(1+2^6\cdot3^3\right)}=\dfrac{3^2\cdot\left(-2\right)}{1+64\cdot27}=\dfrac{-18}{1729}\)
\(B=\dfrac{-7}{9}\cdot\dfrac{4}{11}+\dfrac{-7}{9}\cdot\dfrac{7}{11}+5\dfrac{7}{9}\)
\(=-\dfrac{7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}\)
\(=-\dfrac{7}{9}+5+\dfrac{7}{9}\)
=5
giup minh voi
9.42-7.(-2)3=9.16-7.(-8)=144+56=200