giup to to like
1/2+1/6+1/12+1/20+...+1/90
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1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 + 1/110 + 1/132 = 2/3,
Đúng 100%!
Ai tk cho mình mình tk lại.
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}+\frac{1}{110}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}+\frac{1}{10.11}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}\)
\(=1-\frac{1}{11}\)
\(=\frac{10}{11}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
\(=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+\frac{1}{6\times7}+\frac{1}{7\times8}+\frac{1}{8\times9}+\frac{1}{9\times10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
( Gạch bỏ các phân số giống nhau )
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
Chúc bn học tốt !!!!
1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90
=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8+1/8x9+1/9x10
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10
=1-1/10
=9/10
k đúng cho mk nh!!!
\(S1=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
\(S1=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(S1=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(S1=1-\frac{1}{10}\)
\(S1=\frac{9}{10}\)
CHÚC BN HC GIỎI !!!!!!!!!! TỨ DIỆP THẢO
S=\(\frac{1}{1.2}+\frac{1}{2.3}+...............+\frac{1}{9.10}\)
=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...............+\frac{1}{9}-\frac{1}{10}\)
=\(1-\frac{1}{10}\)
=\(\frac{9}{10}\)
\(A=1-1-\dfrac{5}{6}+1+\dfrac{7}{12}-1-\dfrac{9}{20}+1+\dfrac{11}{30}-1-\dfrac{13}{42}+1+\dfrac{15}{56}-1-\dfrac{17}{72}+1+\dfrac{19}{90}\)
\(=1-\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}+\dfrac{1}{10}\)
=1/2+1/10
=5/10+1/10=6/10=3/5
Câu 1:
1/2 + 1/6 + 1/12+...+1/90
=1/1×2 + 1/2×3 + 1/3×4 +...+1/9×10
=1/1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10
(Chắc chỗ này bạn hiểu)
TRIỆT TIÊU CÁC PHÂN SỐ GIỐNG NHAU, TA CÒN:
=1/1 -1/10
=9/10
Câu 2:
2abc = 9 x abc
2000+ abc = 9 x abc
2000 =9 x abc - abc
2000 = 8 × abc
abc = 2000÷8
abc = 250
1/2+1/6+1/12+...+1/90=1/(1.2)+1/(2.3)+1/(3.4)+...+1/(9.10)
=1/1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10
=1-1/10
=9/10
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+..+\frac{1}{90}=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=1-\frac{1}{10}=\frac{9}{10}\)
dấu "." là nhân nhé
\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)
\(A=1-\frac{1}{10}\)
\(A=\frac{9}{10}\)
1/2+1/6+1/12+1/20+...+1/90
=1/1.2+1/2.3+1/3.4+...+1/9.10
=1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10
=1-1/10
=9/10
1/2 + 1/6 + 1/12 + 1/20 +...1/90 = 1/1.2 + 1/2.3+ 1/3.4 +...+1/9.10
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - ...-1/10
= 1/1 - 1/10 = 9/10
Giải pt
(1+1/2)+(1+1/6)+(1+1/12)+(1+1/20)+.
..+{1+1/[x(x+1)]}=8,9
<=>x+1/2+1/6+...+1/[x(x+1)]=8,9
<=>x+1/(1*2)+1/(2*3)+...+1/[x(x+1)]=8,...
<=>x+1-1/2+1/2-1/3+..+1/x-1/(x+1)=8,9
<=>x+x/(x+1)=8,9
<=>x^2+2x=8,9x+8,9<=>x=8