Giá trị của phép tính
7/2+33/7-75/14
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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
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Tính nhanh : 25 + 33 + 75 + 67 = (25 + 75) + ( 33+ 67 ) = 200
Đáp án cần chọn là C
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P/s: Bài này chỉ tính được giá trị "gần đúng" của biểu thức thôi nhé!
\(\frac{21}{54}+\frac{3}{75}:\frac{\left(\frac{39}{65}+0,415-\frac{33}{600}\right)\frac{21}{91}}{7^2-18,25+13\frac{15}{36}-16\frac{17}{102}}\)
\(\Leftrightarrow\frac{21}{54}+\frac{3}{75}:\frac{\left(0,6+0,415-0,055\right)0,23}{49-18,25+\frac{483}{36}-\frac{1649}{102}}\)
\(\Leftrightarrow\frac{21}{54}+\frac{3}{75}:\frac{\left(0,6+0,415-0,055\right)0,23}{49-18,25+13,41-16,1}\)
\(\Leftrightarrow\frac{21}{54}+\frac{3}{75}:\frac{0,96.0,23}{28,06}\Leftrightarrow\frac{21}{54}+\frac{3}{75}:\frac{0,2208}{28,06}\)
\(\Leftrightarrow\frac{21}{54}+\left(\frac{3}{75}:\frac{0,2208}{28,06}\right)\Leftrightarrow\frac{21}{54}+\left(\frac{3}{75}.\frac{28,06}{0,2208}\right)=\frac{21}{54}+\frac{61}{12}=\frac{197}{36}\)
P/s: Giải bài này mà mệt cả đầu =((
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\(a,x^4-2x^3+6x^2+x+14\\ =\left(x^4-3x^3+7x^2\right)+\left(x^3-3x^2+7x\right)+\left(2x^2-6x+14\right)\\ =\left(x^2-3x+7\right)\left(x^2+x+2\right):\left(x^2-3x+7\right)=x^2+x+2\)
Ta có \(x^2+x+2=x^2+x+\dfrac{1}{4}+\dfrac{7}{4}=\left(x+\dfrac{1}{2}\right)^2+\dfrac{7}{4}\ge\dfrac{7}{4}>0\)
Vậy ...
\(b,A=x^3+3xy+y^3\\ A=\left(x+y\right)\left(x^2-xy+y^2\right)+3xy\\ A=x^2-xy+y^2+3xy\\ A=x^2+2xy+y^2=\left(x+y\right)^2=1\)
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x – 17 = 33 : 3
x – 17 = 11
x = 11 + 17
x = 28
Đáp án cần chọn là C
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a/\(30,395:217=0,14\)(dư 0,015)
b/\(\dfrac{5}{7}:\dfrac{9}{14}-\dfrac{17}{18}\)
\(=\dfrac{5}{7}\times\dfrac{14}{9}-\dfrac{17}{18}\)
\(=\dfrac{10}{9}-\dfrac{17}{18}\)
\(=\dfrac{20}{18}-\dfrac{17}{18}\)
\(=\dfrac{3}{18}=\dfrac{1}{6}\)
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X x 4 – 17 = 33 : 3
x x 4– 17 = 11
X x 4 = 11 + 17
X x 4 = 28
X = 28 : 4
X = 7
Đáp án cần chọn là B
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\(\dfrac{4}{7}-\dfrac{1}{3}< \dfrac{1}{2}-\dfrac{2}{9}\)
\(\dfrac{125}{100}-\dfrac{48}{64}< \dfrac{6}{7}-\dfrac{14}{28}\)
\(\dfrac{7}{5}-\dfrac{22}{25}=\dfrac{1}{5}+\dfrac{4}{10}\)\(\dfrac{45}{75}+\dfrac{22}{33}>\dfrac{4}{5}+\dfrac{4}{6}\)
\(\frac{7}{2}+\frac{33}{7}-\frac{75}{14}=\)
\(\frac{115}{14}-\frac{75}{14}=\)
\(\frac{95}{7}\)
#Wind
\(\frac{7}{2}+\frac{33}{7}-\frac{75}{14}\)
\(=\) \(\frac{115}{14}\)\(-\)\(\frac{75}{14}\)
\(=\) \(\frac{40}{14}\)