tính A =2019x2021+4 phần 2021x2020-2017
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a=(2021-2019) x 2020/2019x2020+(2020 +1)x7+2013
=1x2020/2019x2020+2020x7+1x7+2013
=2020/(2019+7)x2020+2020
=2020/(2019+1+70) x2020
=2020/2027 x2020
=2020/4112783
Mình cảm ơn ạ nếu bạn có thời gian làm giúp mình câu b c d đc k ạ?:3
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\(a,50\%+\dfrac{7}{12}-\dfrac{1}{2}\\ =\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\\ =\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\\ =\dfrac{7}{12}\\ b,2022\times67+2022\times43-2022\times10\\ =2022\times\left(67+43-10\right)\\ =2022\times100\\ =202200.\\ c,125-25:3\times12\)
\(=25\times5-25:3\times12\\ =25\times\left(5-\dfrac{1}{3}\right)\times12\\ =25\times\dfrac{14}{3}\times12\\ =1400\)
a,50%+127−21=21+127−21=(21−21)+127=127b,2022×67+2022×43−2022×10=2022×(67+43−10)=2022×100=202200.c,125−25:3×12
=25×5−25:3×12=25×(5−13)×12=25×143×12=1400=25×5−25:3×12=25×(5−31)×12=25×314×12=1400
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\(2020^2-2019.2021=2020^2-\left(2020-1\right)\left(2020+1\right)\)
\(=2020^2-\left(2020^2-2020+2020-1\right)=2020^2-\left(2020^2-1\right)\)
\(=2020^2-2020^2+1=1\)
`2020^2-2019xx2021`
`=2020xx2020-2019xx2021`
`=2020xx2020-2019xx(2020+1)`
`=2020xx2020-(2019xx2020+2019)`
`=2020xx2020-2019xx2020-2019
`=2020xx(2020-2019)-2019`
`=2020xx1-2019`
`=2020-2019`
`=1`
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tích của A và B so sánh
A = 2 020 X 2 020 = 4 080 400
A = 4 080 400
B = 2 019 X 2 021 = 4 080 399
B = 4 080 399
Vậy 4 080 400
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A,(2016*2017-1)/2015*2017+2016
=2015*2017+2016/2015*2017+2016
=1
B,18*(1919/2121+888/999)
=18*(19/21+8/9)
=18*(19/21)+18*(8/9)=114/7+16=16+2/7+16=32/2/7
c,gọi s=1/2+1/4+...+1/32
2s=1+1/2+...+1/16
2s-s=(1+1/2+...+1/16)-(1/2+1/4+...+1/32)
s=1-1/32=31/32
\(\frac{2019\times2021+4}{2021\times2020-2017}=\frac{2019\times2021+4}{2021\times\left(2019+1\right)-2017}=\frac{2019\times2021+4}{2021\times2019+2021-2017}\)
\(=\frac{2019\times2021+4}{2021\times2019+4}=1\)