3÷4=
16÷50=
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\(\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{6-4\sqrt{2}}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{67-16\sqrt{3}}}}\)
\(\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{6-4\sqrt{2}}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{67-16\sqrt{3}}}}\)
\(=\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{\left(\sqrt{2}-2\right)^2}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{\left(\sqrt{3}-8\right)^2}}}\)
\(=\sqrt{4\sqrt{2}-\sqrt{4+16\left(2-\sqrt{2}\right)}}+\sqrt{\sqrt{3}+\sqrt{228+50\left(8-\sqrt{3}\right)}}\)
\(=\sqrt{4\sqrt{2}-\sqrt{36-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{628-50\sqrt{3}}}\)
\(=\sqrt{4\sqrt{2}-\sqrt{\left(4\sqrt{2}-2\right)^2}}+\sqrt{\sqrt{3}+\sqrt{\left(\sqrt{3}-25\right)^2}}\)
\(=\sqrt{4\sqrt{2}-4\sqrt{2}+2}+\sqrt{\sqrt{3}+25-\sqrt{3}}\)
\(=\sqrt{2}+5\)
\(\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{6-4\sqrt{2}}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{67-16\sqrt{3}}}}=\sqrt{4\sqrt{2}-\sqrt{4+16\sqrt{\left(2-\sqrt{2}\right)^2}}}+\sqrt{\sqrt{3}+\sqrt{228+50\sqrt{\left(8-\sqrt{3}\right)^2}}}=\sqrt{4\sqrt{2}-\sqrt{4+32-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{228+400-50\sqrt{3}}}=\sqrt{4\sqrt{2}-\sqrt{36-16\sqrt{2}}}+\sqrt{\sqrt{3}+\sqrt{628-50\sqrt{3}}}=\sqrt{4\sqrt{2}-4\sqrt{2}+2}+\sqrt{\sqrt{3}+25-\sqrt{3}}=\sqrt{2}+\sqrt{25}=5+\sqrt{2}\)
a) \(...=16.\left(36-37\right)=16.\left(-1\right)=-16\)
b) \(...=9.3+9.50=9.\left(3+50\right)=9.53=477\)
c) \(...=2.\left(\left(5.16-18\right)+36:18\right)=2.\left(70+2\right)=2.72=144\)
d) \(...=5\left(48:8+44\right)=5\left(6+44\right)=5.50=250\)
e) \(...=20-6=14\)
f) \(...=50+13-2=61\)
a) 16 . 36 - 16 . 37
= 16 . (36 - 37)
= 16 . (-1)
= -16
b) 36 : 4 . 3 + 9 . 50
= 9 . 3 + 9 . 50
= 9 . (3 + 50)
= 9 . 53
= 477
c) 2 . (5 . 16 - 18) + 36 : 18 . 2
= 2 . (80 - 18) + 2 . 2
= 2 . 62 + 2 . 2
= 2 . (62 + 2)
= 2 . 64
= 128
Tìm x:
a) (x²-16)(3x+2)=
b) 50% .x + ⅗(x-5) =
c) \(\dfrac{3}{4}+\dfrac{1}{4}:\:x\:=\:-\dfrac{1}{3}\)
a: \(12:\dfrac{3}{4}+75\%\cdot\dfrac{1}{2}-16\cdot50\%\)
\(=12\cdot\dfrac{4}{3}+\dfrac{3}{4}\cdot\dfrac{1}{2}-16\cdot0,5\)
\(=16-8+\dfrac{3}{8}\)
\(=8,375\)
b: \(75\%\cdot4+22,5:3-1\dfrac{3}{5}\)
\(=0,75\cdot4+7,5-1,6\)
\(=3+7,5-1,6\)
=10,5-1,6
=8,9
DẶT A= BIỂU THỨC TRÊN
A=2+1+1+..+1-(1/4+1/9+...+1/2500)
ĐẶT S=1/4+1/9+...+1/2500
S=1/2^2+1/3^2+...+1/50^2
SÓ SỐ HẠNG CỦA S:
(50-2)/1+1=49
SUY RA
1+1+...+1=49
SUY RA A=2+49-S
A=51-S
TAO CÓ :
S<1/1.2+1/2.3+...+1/49.100
S<1-1/2+1/2-1/3+...+1/49-1/50
S<1-1/50
S<49/50
SUY RA A>51-49/50
SUY RA A>50
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
a) \(\dfrac{16}{24}-\dfrac{1}{3}=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
b ) \(\dfrac{4}{5}-\dfrac{12}{60}=\dfrac{4}{5}-\dfrac{1}{5}=\dfrac{4}{5}\)
c ) \(\dfrac{35}{50}-\dfrac{3}{10}=\dfrac{7}{10}-\dfrac{3}{10}=\dfrac{4}{10}=\dfrac{2}{5}\)
d ) \(\dfrac{21}{28}-\dfrac{1}{4}=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}\)
\(3\div4=0,75\)
\(16\div50=0,32\)
_Chúc bạn học tốt_
3:4=0,75
16:50=0,32