3 | + | 3 | + … + | 3 | = | |
3 . 5 | 5 . 7 | 121 . 123 |
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 123 - ( 155 + 123 - 55 )
= 123 - 155 - 123 + 55
= 123 - 123 -155 + 55
= 0 - 155 + 55
= -155 + 55
= -100
b, -315 - ( -43 + 17 - 315 )
= -315 + 43 -17 + 315
= -315 + 315 + 43 -17
= 0 + 26 = 26
c. -15 .49 - 15. 51
= 15. -49 - 15 . 51
= 15 ( -49 - 51 )
= 15. ( -100 )
= -1500
d. -35 . 47 - 35 . 50 + 35 . -3
= 35 ( -47 - 50 + -3 )
=35. -100
= -3500
a, 123-(155+123-55)=123-223=-100
b,-315-(-43+17-315)=26
c,-15*49-15*51=-1500
d, -35.47-35.50+35.-3=-38.97
![](https://rs.olm.vn/images/avt/0.png?1311)
a,
128-3x-12=23
3x=128-12-23
3x=93
x=93:3
= 31
b,
(12x+84+55):5=35
12x+84+55=35.5
12x+84+55=175
12x=175-55-84
12x=36
x=36:12
x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 18.123 + 9.456.2 + 3.6
= 18.123 + 18.456 + 18
= 18 ( 123 + 456 + 1 )
= 18 . 580
= 10440
b) 1+4+7+10+...+49+52+55+58-410
= ( 58 + 1 ) . 20 : 2 - 410
= 590 - 410
= 180
![](https://rs.olm.vn/images/avt/0.png?1311)
(x-13)2 =36
(x-13)2=62
*x-13=6 *x-13=-6
x=6+13 x=-6+13
x=19 x=7
Vậy x=19 hoặc x=7
(x-3)3=(-27)
(x-3)3=(-3)3
x-3=-3
x=-3+3
x=0
Vậy x=0
(x+4)2-9=55
(x+4)2=55+9
(x+4)2=64
(x+4)2=82
*x+4=8 *x+4=-8
x=8-4 x=-8-4
x=4 x=-12
Vậy x=4 hoặc x=-12
(x-5)3=123
Vô lí vì 123 ko chuyển sang được mũ 3
Vậy \(x\in\varnothing\)
2) \(\left(x-13\right)^2=36\)
\(\Leftrightarrow\left(x-13\right)^2=6^2\)
\(\Leftrightarrow x-13=6\)
\(\Leftrightarrow x=19\)
Vậy x = 19
3) \(\left(x-3\right)^3=\left(-27\right)\)
\(\Leftrightarrow\left(x-3\right)^3=\left(-3\right)^3\)
\(\Leftrightarrow x-3=\left(-3\right)\)
\(\Leftrightarrow x=0\)
Vậy x = 0
4) \(\left(x+4\right)^2-9=55\)
\(\Leftrightarrow\left(x+4\right)^2=64\)
\(\Leftrightarrow\left(x+4\right)^2=8^2\)
\(\Leftrightarrow x+4=8\)
\(\Leftrightarrow x=4\)
Vậy x = 4
5) \(\left(x-5\right)^3=123\)
\(\Leftrightarrow x\in\left\{\varnothing\right\}\)
Vì 123 sẽ không thể chuyển thể thành mũ 3 đc
![](https://rs.olm.vn/images/avt/0.png?1311)
a, bạn tự làm
b, \(B=\dfrac{5^2}{5}\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+...+\dfrac{1}{101}-\dfrac{1}{106}\right)\)
\(=5\left(1-\dfrac{1}{106}\right)=\dfrac{5.105}{106}=\dfrac{525}{106}\)
c, đk : \(x\ne\dfrac{2}{3}\)
Ta có : \(\left|x-1\right|=2\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)(tm)
Với x = 3 suy ra \(C=\dfrac{2.9+9-1}{3.3-2}=\dfrac{26}{7}\)
Với x = -1 suy ra \(C=\dfrac{2-3-1}{-3-2}=\dfrac{-2}{-5}=\dfrac{2}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
B=2006 * 2008 -3 / 2005 + 2005 * 2008
B=(2005+1)* 2008 -3 / 2005 +2005 *2008
B=2005 * 2008 + 2008 -3 / 2005 +2005*2008
B=2005 * 2008 + 2005 / 2005 +2005 * 2008
B= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Xét \(123+\left(-3\right)=120< 123\)
\(\Rightarrow123+\left(-3\right)< 123\)
b) Xét \(\left(-97\right)+7=\left(-90\right)>\left(-97\right)\)
\(\Rightarrow\left(-97\right)+7>\left(-97\right)\)
c) Xét \(\left(-55\right)+\left(-15\right)=\left(-70\right)< \left(-55\right)\)
\(\Rightarrow\left(-55\right)+\left(-15\right)< \left(-55\right)\)
\(\frac{3}{3\times5}+\frac{3}{5\times7}+...+\frac{3}{121\times123}\)
\(=\frac{3}{2}\times\left(\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{121\times123}\right)\)
\(=\frac{3}{2}\times\left(\frac{5-3}{3\times5}+\frac{7-5}{5\times7}+...+\frac{123-121}{121\times123}\right)\)
\(=\frac{3}{2}\times\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{121}-\frac{1}{123}\right)\)
\(=\frac{3}{2}\times\left(\frac{1}{3}-\frac{1}{123}\right)\)
\(=\frac{20}{41}\)
\(\frac{3}{3x5}\)+ \(\frac{3}{5x7}\)+....+ \(\frac{3}{121x123}\)
(\(\frac{1}{3}\)- \(\frac{1}{5}\)+ \(\frac{1}{5}\)- \(\frac{1}{7}\)+ ...+ \(\frac{1}{121}\)- \(\frac{1}{123}\))
=\(\frac{1}{3}\)- \(\frac{1}{123}\)
=\(\frac{40}{123}\)
Học tốt!