Tổng 10 mũ 2021 +8 ko chia hết cho những số nào sau đây:
A.9
B.9
C.2
D.5
Nhanh giúp mình nhé mình đang cần gấp
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Hiệu của số lớn nhất và số bé nhất là:
` 2 + 2 = 4`
Số thứ nhất là:
`(600 - 4):2 = 298`
Số thứ hai là:
`298 + 2 = 300`
Số thứ ba là:
`300 + 2 = 302`
Đáp số: Số thứ nhất: `298;` số thứ hai: `300;` số thứ ba: `302`
19 has worked
20 have lived - was
21 isn't - is cooking
22 Do you know - is talking
23 broke - was playing
24 has just repaired
25 washes
26 was listening
27 are playing
28 Have you cried
29 is living - prefers
30 wouldn't have finished
31 was watching
32 is going to invite
33 know - to answer
34 are going
35 have collected
36 is repairing - has been working
37 was walking - saw
38 haven't finished
39 haven't seen - left
40 have been walking
41 have been learning
42 have stayed
43 left
44 has driven
45 is coming
46 was working
47 was fishing
48 will like
Đặt `A= 1/3 + 1/(3^2) + 1/(3^3) + ... + 1/(3^99) + 1/(3^100)`
`3A= 3. (1/3 + 1/(3^2) + 1/(3^3) + ... + 1/(3^99) + 1/(3^100))`
`3A= 1 + 1/3 + 1/(3^2) + ... + 1/(3^98) + 1/(3^99)`
`3A - A = (1 + 1/3 + 1/(3^2)+... + 1/(3^98) + 1/(3^99)) - (1/3 + 1/(3^2) + 1/(3^3) + ... + 1/(3^99) + 1/(3^100))`
`2A = 1 - 1/(3^100)`
`A = (1 - 1/(3^100))/2`
Vậy: `1/3 + 1/(3^2) + 1/(3^3) + ... + 1/(3^99) + 1/(3^100) = (1-1/(3^100))/2`
A = \(\dfrac{1}{3}\) + \(\dfrac{1}{3^2}\) + \(\dfrac{1}{3^3}\) + ... + \(\dfrac{1}{3^{99}}\) + \(\dfrac{1}{3^{100}}\)
3A = 1 + \(\dfrac{1}{3}\) + \(\dfrac{1}{3^2}\)+...+ \(\dfrac{1}{3^{98}}\) + \(\dfrac{1}{3^{99}}\)
3A - A = (1+ \(\dfrac{1}{3}\) + \(\dfrac{1}{3^2}\) + ...+\(\dfrac{1}{3^{98}}\) + \(\dfrac{1}{3^{99}}\)) - (\(\dfrac{1}{3}\) + \(\dfrac{1}{3^2}\)+..+\(\dfrac{1}{3^{99}}\)+\(\dfrac{1}{3^{100}}\))
A.(3 - 1) = 1 + \(\dfrac{1}{3}\)+\(\dfrac{1}{3^2}\)+..+\(\dfrac{1}{3^{98}}\)+ \(\dfrac{1}{3^{99}}\) - \(\dfrac{1}{3}\) - \(\dfrac{1}{3^2}\) - ...- \(\dfrac{1}{3^{99}}\) - \(\dfrac{1}{3^{100}}\)
A x 2 = (1 - \(\dfrac{1}{3^{100}}\)) + (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) + (\(\dfrac{1}{3^{98}}\) - \(\dfrac{1}{3^{98}}\)) + (\(\dfrac{1}{3^{99}}\) - \(\dfrac{1}{3^{99}}\))
A x 2 = 1 - \(\dfrac{1}{3^{100}}\) + 0 + 0 + ..+ 0
A x 2 = 1 - \(\dfrac{1}{3^{100}}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{2.3^{100}}\)
Vì 3311 = 11 . 301 nên 3311 có ước là 11 và 301. Vậy 3311 là một hợp số.
C
\(10\) chia hết cho 5 nên \(10^{2021}\) chia hết cho 5
Mà 8 ko chia hết cho 5
Nên \(10^{2021}+8\) không chia hết cho 5
D đúng