tìm a và b sao cho f(x) chia hết cho g(x)
f(x)=\(x^4+2x^3-3x^2+ax+b\)
g(x)=\(x^2+3x-1\)
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Theo bài ra:
\(\hept{\begin{cases}1,5\widehat{A}-5^0=\widehat{B}\\2,5\widehat{A}-5^0=\widehat{C}\end{cases}}\Rightarrow\widehat{B}+\widehat{C}=4\widehat{A}-10^0\)
Mà \(\widehat{A}+\widehat{B}+\widehat{C}=180^0\Rightarrow\widehat{A}+4\widehat{A}-10^0=180^0\Rightarrow\widehat{A}=38^0\)
\(\left(2x+3\right)\left(x^2+4x-5\right)\)
\(=2x^3+8x^2-10x+3x^2+12x-15\)
\(=2x^3+12x^2+2x-15\)
Theo mình nghĩ thì:
1. i really enjoyed my holiday last january. While it.........was snowing........(snow) in lowa, the sun ........was shining.....(shine) in Florida
2. While Ted.......was shoveling.....(shovel) snow from his driveway yesterday, his wife....brought...(bring)him a cup of hot chocolate
bạn nam trinh đáp án câu 2 là weren't/ were playing nhé.
Chắc bạn viết thiếu
1. i .......was calling..(call) Mr Wilson AT 9 last night, but he (not be)....wasn't.........at home. He (study)....was studying.........at the library
2.i.........didn't hear...(not hear) the thunder during the storm last night because i...was sleeping.........(sleep)
Chia bình thường thôi mà
chia hộ cái