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\(x\) - (10 - \(x\)) = \(x\) - 22
\(x\) - 10 + \(x\) = \(x\) - 22
2\(x\) - 10 = \(x\) - 22
2\(x\) - \(x\) = -22 + 10
\(x\) = - 12
\(-35-2x=-19\\\Rightarrow2x=-35-(-19)\\\Rightarrow2x=-35+19\\\Rightarrow2x=-16\\\Rightarrow x=-16:2\\\Rightarrow x=-8\\Vậy:x=-8.\)
−35−2x=−19
⇒2x=−35−(−19)
⇒2x=−35+19
⇒2x=−16
⇒x=−16:2
⇒x=−8
Vậy:x=−8.
\(3x+60=-120\\ \Rightarrow3x=-180\\ \Rightarrow x=-60.\)
Vậy ....
`#3107.101107`
`(2x + 1)^3 = 343`
`\Rightarrow (2x + 1)^3 = 7^3`
`\Rightarrow 2x + 1 = 7`
`\Rightarrow 2x = 6`
`\Rightarrow x = 3`
Vậy, `x = 3.`
B = \(\dfrac{4}{7}\) = \(\dfrac{4.4}{7.4}\) = \(\dfrac{16}{28}\); I = \(\dfrac{6}{13}\) = \(\dfrac{6.\left(-2\right)}{13.\left(-2\right)}\) = \(\dfrac{-12}{-26}\)
N = \(\dfrac{-5}{13}\) = \(\dfrac{-5.3}{13.3}\) = \(\dfrac{-15}{39}\); T = \(\dfrac{7}{21}\) = \(\dfrac{7.4}{21.4}\) = \(\dfrac{28}{84}\)
U = \(\dfrac{4}{11}\) = \(\dfrac{4.5}{11.5}\) = \(\dfrac{20}{55}\); O = \(\dfrac{5}{25}\) = \(\dfrac{5.3}{25.3}\) = \(\dfrac{15}{75}\)
H = \(\dfrac{1}{5}\) = \(\dfrac{1.11}{5.11}\) = \(\dfrac{11}{15}\); A = \(\dfrac{5}{8}\) = \(\dfrac{5.5}{8.5}\) = \(\dfrac{25}{40}\)
G = \(\dfrac{-3}{17}\) = \(\dfrac{-3.5}{17.5}\) = \(\dfrac{-15}{85}\); D = \(\dfrac{4}{16}\) = \(\dfrac{4.5}{16.5}\) = \(\dfrac{20}{80}\)
T | H | A | I | B | I | N | H | D | U | O | N | G |
84 | 11 | 25 | -12 | 16 | -12 | -15 | 11 | 80 | 55 | 75 | -15 | 85 |
B. $\frac{4}{7}=\frac{16}{28}$
N. $\frac{-5}{13}=\frac{-15}{39}$
U. $\frac{4}{11}=\frac{20}{55}$
H. $\frac{1}{5}=\frac{11}{55}$
G. $\frac{-3}{17}=\frac{-15}{85}$
I. $\frac{6}{13}=\frac{-12}{-26}$
T. $\frac{7}{21}=\frac{28}{84}$
O. $\frac{5}{25}=\frac{15}{75}$
A. $\frac{5}{8}=\frac{25}{40}$
D. $\frac{4}{16}=\frac{20}{80}$
7960204e+168