1^2/1.2.2^2/2.3.2^3/3.4.4^2/4.5.5^2/5.6.6^2/6.7
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\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)
=>\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}x\right)=\dfrac{23}{27}-\dfrac{5}{9}=\dfrac{8}{27}\)
=>\(2+\dfrac{3}{4}x=\dfrac{7}{9}:\dfrac{8}{27}=\dfrac{7}{9}\cdot\dfrac{27}{8}=\dfrac{21}{8}\)
=>\(\dfrac{3}{4}x=\dfrac{21}{8}-2=\dfrac{5}{8}\)
=>\(x=\dfrac{5}{8}:\dfrac{3}{4}=\dfrac{5}{8}\cdot\dfrac{4}{3}=\dfrac{5}{6}\)

\(\left(x-\dfrac{1}{3}\right):\dfrac{1}{2}+\dfrac{3}{4}=\dfrac{38}{7}\)
=>\(\left(x-\dfrac{1}{3}\right):\dfrac{1}{2}=\dfrac{38}{7}-\dfrac{3}{4}=\dfrac{152-21}{28}=\dfrac{131}{28}\)
=>\(x-\dfrac{1}{3}=\dfrac{1}{2}\cdot\dfrac{131}{28}=\dfrac{131}{56}\)
=>\(x=\dfrac{131}{56}+\dfrac{1}{3}=\dfrac{449}{168}\)

Kia là nhân hay phẩy vậy