\(10^x=20^y.5^y=\left(20.5\right)^y=100^y=10^{10y}\)

Siu ra \(x=10y\)(y nguyên tùy ý)

P/s: Lâu quá không giải dạng này nên cx chả biết có sai sót gì chăng?

10^2y chứ tth

dề sai rùi bạn ơi

1 x 3^y ???

a) \(f\left(x\right)=5x^3-7x^2+x+7+4x^5\)

\(f\left(-1\right)=5.\left(-1\right)^3-7.\left(-1\right)^2+\left(-1\right)+7+4.\left(-1\right)^5\)

\(f\left(-1\right)=\left(-5\right)-7+\left(-1\right)+7+\left(-4\right)\)

\(f\left(-1\right)=-10\)

\(\Rightarrow f\left(x\right)=-10\)

\(g\left(x\right)=4x^5-3x^3-7x^2+2x+5\)

\(g\left(0\right)=4.0^5-3.0^3-7.0^2+2.0+5\)

\(g\left(0\right)=5\)

\(\Rightarrow g\left(x\right)=0\)

\(h\left(x\right)=x^2-4x-5\)

\(h\left(-\frac{1}{2}\right)=\left(-\frac{1}{2}\right)^2-4.\left(-\frac{1}{2}\right)-5\)

\(h\left(-\frac{1}{2}\right)=\frac{1}{4}-\left(-2\right)-5\)

\(h\left(-\frac{1}{2}\right)=-\frac{11}{4}\)

\(\Rightarrow h\left(x\right)=-\frac{11}{4}\)

\(f\left(-1\right)=5\left(-1\right)^3-7\left(-1\right)^2+\left(-1\right)+7+4\left(-1\right)^5\)

\(f\left(-1\right)=-5-7-1+7-4\)

\(f\left(-1\right)=-10\)

\(g\left(0\right)=4.0^5-3.0^3-7.0^2+2.0+5\)

\(g\left(0\right)=0-0-0+0+5\)

\(g\left(0\right)=5\)

\(h\left(-\frac{1}{2}\right)=\left(-\frac{1}{2}\right)^2-4\left(-\frac{1}{2}\right)-5\)

\(h\left(-\frac{1}{2}\right)=\frac{1}{4}-\left(-2\right)-5\)

\(h\left(-\frac{1}{2}\right)=\frac{1}{4}+2-5\)

\(h\left(-\frac{1}{2}\right)=-\frac{11}{4}\)

\(f_{\left(x\right)}-g_{\left(x\right)}=2x^5+x^4+1x^2+x+1-\left(2x^5+x^4-x^2+1\right)\)

                     \(=2x^5+x^4+1x^2+x+1-2x^5-x^4+x^2-1\)

                       \(=\left(2x^5-2x^5\right)+\left(x^4-x^4\right)+\left(1x^2+x^2\right)+x+\left(1-1\right)\)

                       \(=2x^2+x\)

+, Đặt \(2x^2+x=0\)

     \(\Leftrightarrow x.2x=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\2x=0\end{cases}}\Leftrightarrow x=0\)

ak bạn thêm kết kuận nha!

\(\frac{-15}{12}x+\frac{3}{2}=\frac{1}{3}x-\frac{1}{2}\)

\(\Leftrightarrow\frac{-15}{12}x=\frac{1}{3}x-\frac{1}{2}-\frac{3}{2}\)

\(\Leftrightarrow\frac{1}{3}x-\frac{1}{2}-\frac{3}{2}=\frac{-15}{12}x\)

\(\Leftrightarrow\frac{1}{3}x-\left(\frac{1}{2}+\frac{3}{2}\right)=\frac{-15}{12}x\)

\(\Leftrightarrow2=\frac{1}{3}x-\frac{-5}{4}x\)

\(\Leftrightarrow x\left(\frac{1}{3}+\frac{5}{4}\right)=2\)

\(\Leftrightarrow\frac{19}{12}x=2\)

\(\Leftrightarrow x=2\times\frac{12}{19}\)

\(\Leftrightarrow x=\frac{24}{19}\)

\(\frac{x+2}{0,5}=\frac{2x+1}{2}\)

\(\Leftrightarrow2\left(x+2\right)=\left(2x+1\right)\times\frac{1}{2}\)

\(\Leftrightarrow2x+4=x+\frac{1}{2}\)

\(\Leftrightarrow2x+4-x=\frac{1}{2}\)

\(\Leftrightarrow2x-x=\frac{1}{2}-4\)

\(\Leftrightarrow x=-3,5\)

\(\Leftrightarrow x=-3,5\)