1. …Have you ever drove……………………(you/ ever/ drive) on the wrong side of the road?

2. My family …flew…………………… (fly) back from our Hong Kong holiday two days ago.

3. Right now, the students …are learning…………………… (learn) road signs in the schoolyard.

4. Usually Oanh …walks…………………… (walk) to school, but this week she …will ride…………………… (ride) her bike.

5. The driver was so drunk that he …lost…………………… (lose) control of his car.

6. If I have enough money, I …will buy…………………… (buy) a racing car.

7. My father …taught…………………… (teach) me to ride a bike when I was seven.

8. Transport used …to be…………………… (be) much slower three hundred years ago.

9. Saudi women weren’t allowed …to drive…………………… (drive) a car until recently.

10. In South Africa, you have to let animals ……go………………… (go) first.

1. ………Have you ever drove………………(you/ ever/ drive) on the wrong side of the road?

2. My family …………flew…………… (fly) back from our Hong Kong holiday two days ago.

3. Right now, the students ……are……learning…………… (learn) road signs in the schoolyard.

4. Usually Oanh …………walks…………… (walk) to school, but this week she …will ride……………… (ride) her bike.

5. The driver was so drunk that he …………lost…………… (lose) control of his car.

6. If I have enough money, I …………will buy…………… (buy) a racing car.

7. My father …………taught…………… (teach) me to ride a bike when I was seven.

8. Transport used ………to be……………… (be) much slower three hundred years ago.

9. Saudi women weren’t allowed ………to drive……………… (drive) a car until recently.

10. In South Africa, you have to let animals …………go…………… (go) first.

Bạn tự vẽ hình nha!!! ^^

Do \(\Delta ABC\) cân tại A => \(\widehat{ABC}\)=\(\widehat{ACB}\)(1)

D nằm trên tia đối của BA => \(\widehat{ABC}+\widehat{CBD}=180^o\)(2)

Từ (1) và (2)=> \(\widehat{ACB}+\widehat{CBD}=180^o\)

Mà \(\widehat{ACB}+\widehat{BCD}< 180^o\)

Nên \(\widehat{DBC}>\widehat{BCD}\)

=> DC >DB ( cạnh đối diện)

(đpcm)

Học tốt!!

#Bo

Tham khảo:  Câu hỏi của Thu Trang

Bằng nhau

Dễ thấy y + 2018 > y + 2017 nên 2^x > 2^z

\(\Rightarrow2^x⋮2^z\)

hay y + 2018 \(⋮\) y + 2017

=> y + 2017 + 1 \(⋮\) y + 2017

Vì y + 2017 \(⋮\) y + 2017 nên 1 \(⋮\) y + 2017

\(y+2017\in\left\{\pm1\right\}\)

+) \(y+2017=1\Rightarrow y=-2016\)

Lúc đó x = 1; z = 0  (tm)

+) \(y+2017=-1\Rightarrow y=-2018\)

Lúc đó \(2^z=-1\)(vô lí)

Vậy x = 1;y = -2016;z=0