hái thì biết

Gọi số đóa là a, so nguoi là b

TA có :b-3=a

           2b/3+3=a

=>2b/3+3=b-3=>1/3xb=6=>b=18=>a=15

Vậy

thank

\(P=xy\left(x+4\right)\left(y-2\right)+6x\left(x+4\right)+5y\left(y-2\right)+243\)

\(=y\left(y-2\right)\left[x\left(x+4\right)+5\right]+6\left[x\left(x+4\right)+5\right]+213\)

\(=y\left(y-2\right)\left(x^2+4x+5\right)+6\left(x^2+4x+5\right)+213\)

\(=\left(x^2+4x+5\right)\left(y^2-2y+6\right)+213\)

\(=\left[\left(x+2\right)^2+1\right].\left[\left(y-1\right)^2+5\right]+213\ge1.5+213=218\)

Dấu "=" xảy ra khi \(\hept{\begin{cases}x+2=0\\y-1=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\y=1\end{cases}}\)

Vậy \(P_{min}=218\Leftrightarrow\hept{\begin{cases}x=-2\\y=1\end{cases}}\)

mơn nha bn

Bạn tham khảo ở link này nhé:

https://olm.vn/tin-tuc/Bai-toan-215.html

đáp án

Ta có thể thêm dấu cộng vào giữa các số như sau:
\(\text{8+7+6+5+43+21=90}\)

vvvvvvvvvvvvv

vật lý ak 

\(\hept{\begin{cases}4x-3=a\\3x-2=b\end{cases}}\Rightarrow a^3+b^3=\left(a+b\right)^3\)

\(\Leftrightarrow3ab\left(a+b\right)=0\Leftrightarrow3\left(4x-3\right)\left(3x-2\right)\left(7x-5\right)=0\Leftrightarrow...\)

I.

1.has visited 

2.teacher taught

3.Have you ever eaten

4.moves

5.to barn

6.have never came

II.

1.I'm taken to the beach by him once a month

2.The essay should be written by us carefully 

3.The trees can be planted along the street (by them)

4.sai đề

5.sai đề

\(x^2y+xy^2+x+y=2018\)

\(\Leftrightarrow xy\left(x+y\right)+\left(x+y\right)=2018\)

\(\Leftrightarrow\left(xy+1\right)\left(x+y\right)=2018\Leftrightarrow12\left(x+y\right)=2018\)

\(\Leftrightarrow x+y=\frac{1009}{6}\)

\(x^2+y^2=\left(x+y\right)^2-2xy=\left(\frac{1009}{6}\right)^2-2.11=...\)