Yêu nhau cau sáu bổ ba
Ghét nhau cau sáu bổ ra làm mười
Số người tính đã tám mươi
Cau mười năm quả hỏi người ghét yêu
TÍNH SỐ NGƯỜI GHÉT, NGƯỜI YÊU
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1.will phone
2.will sit
3.will watch
4.will work
5.will you do...
6.will wait
7.will Tom meet
8.will get
9.will study
10.will use
1. Mai....are going to phone..........(phone) her grandparents at seven o'clock tomorrrow
2. This time next week,I (sit)......will sit.....on the beach in Nha Trang
3. At 7 o'clock tonight,I ( watch) ......am going to watch .......... the news
4. At 3 o'clock tomorrow, I (work)......am going to work ........in my office
5. What ( you/do).........are you going to do..........this time tomorrow ?
6. At 5o'cloock tomorrow afternoon, he ( wait) .......is going to wait ............for his train
7. ( Tom/meet)..........Will Tom meet........... me when I arrive at the airport?
8. This time tomorrow , we ( get)..............are going to get............ready to go out
9. At 9 o'clock tomorrow morning,she ( study) ......is going to study......... in the library
10. We.....will use ....... a universal translator to deal with any foreign language ( use )
\(\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{a+d}\ge\frac{a-d}{a+b}\)
\(\Leftrightarrow\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{a+d}-\frac{a-d}{a+b}\ge0\)
\(\Leftrightarrow\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{a+d}+\frac{d-a}{a+b}\ge0\)
\(\Leftrightarrow\left(\frac{a-b}{b+c}+1\right)+\left(\frac{b-c}{c+d}+1\right)+\left(\frac{c-d}{a+d}+1\right)+\left(\frac{d-a}{a+b}+1\right)\ge4\)
\(\Leftrightarrow\frac{a+c}{b+c}+\frac{b+d}{c+d}+\frac{c+a}{a+d}+\frac{d+b}{a+b}\ge4\)
\(\Leftrightarrow\left(a+c\right)\left(\frac{1}{b+c}+\frac{1}{a+d}\right)+\left(b+d\right)\left(\frac{1}{c+d}+\frac{1}{a+b}\right)\ge4\)(1)
Áp dụng BĐT AM-GM ta có:
\(\frac{a+c}{b+c}+\frac{b+d}{c+d}+\frac{c+a}{a+d}+\frac{d+b}{a+b}\ge\)\(\left(a+c\right)\frac{2}{\sqrt{\left(b+c\right)\left(a+d\right)}}+\left(b+d\right)\frac{2}{\sqrt{\left(c+d\right)\left(a+b\right)}}\ge\frac{4\left(a+c\right)}{a+b+c+d}+\frac{4\left(b+d\right)}{a+b+c+d}=\frac{4\left(a+b+c+d\right)}{a+b+c+d}=4 \left(2\right)\)Từ (1) và (2) \(\Rightarrow\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{a+d}\ge\frac{a-d}{a+b}\)
Dấu " = " xảy ra \(\Leftrightarrow\hept{\begin{cases}\frac{1}{b+c}=\frac{1}{a+d}\\\frac{1}{c+d}=\frac{1}{a+b}\end{cases}}\Leftrightarrow\hept{\begin{cases}b+c=a+d\\c+d=a+b\end{cases}}\Leftrightarrow a=b=c=d\)
vì sao
(a+c)(2/căn bậc 2 của(b+c)(a+d))+(b+d)(2/căn bậc 2 của (c+d)(a+b))
>=(4(a+c)/a+b+c+d) +4(b+d)/a+b+c+d
(căn bậc 2 máy mink ko viết đc)
Ta có: \(\frac{x^2}{y^2}+\frac{y^2}{x^2}\ge\frac{x}{y}+\frac{y}{x}\)
\(\Leftrightarrow\frac{x^4+y^4}{x^2y^2}\ge\frac{x^2+y^2}{xy}\Leftrightarrow\frac{x^4+y^4}{x^2y^2}\ge\frac{x^3y+xy^3}{x^2y^2}\)
\(\Leftrightarrow x^4+y^4\ge x^3y+xy^3\Leftrightarrow x^4+y^4-x^3y-xy^3\ge0\)
\(\Leftrightarrow x^3\left(x-y\right)-y^3\left(x-y\right)\ge0\Leftrightarrow\left(x-y\right)^2\left(x^2+xy+y^2\right)\ge0\)(đúng)
Các phép biến đổi là tương đương suy ra đpcm
Dấu "=" xảy ra khi x=y
tonardo
aid
noise
put out
evacuate
part2
1.to ; 2.at; 3.have; 4.and; 5.from
Part 1:, Use the words from the box to complete the sentences : put out, tonardo, evacuate, noise pollution, aid
5,The police had to...house fire......the village to public shelter before the volcano started to erupt
Part 2: complete the email. Write ONE word for each space
Hi Marie,
Can you help me? I want(1).....to.........make a birthday card for my grandma. I know you're very good(2)........at........art, so (3)......has...........you got any ideas? Grandma loves animals. She has three cats, two dogs(4).........and.........two horses. Do you think I should paint one(5)........of.........her animals for the cards?
Vt | Tgian | Q.duong | |
luc di | 45 | x | 45x |
luc ve | 60 | x-50 | 60(x-50) |
ta co ph trinh
45x=60(x-50)
x=200 km
cho mk cai h nha
Số người ghét: 50
Số người yêu: 30
Suy luận logic là ra.
Bài này Tiểu Học đâu ra lớp 8.
bạn giải theo phương trình sẽ là lớp 8, hãy suy nghĩ tinh tế lên một chút