giải phương trình: (x2 + 1)2 + 3x(x2 + 1) + 2x2 = 0
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OA
3
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NT
0
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13 tháng 3 2019
My mother angry sees me play video game
Chỉ huy
13 tháng 3 2019
Answer :
My mother was angry when she saw me played video game.
Study well !!
FS
5
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T
20 tháng 8 2019
Làm luôn:v
\(3\left(a^4+b^4+c^4\right)\ge\left(a+b+c\right)\left(a^3+b^3+c^3\right)\)
\(\Leftrightarrow\left(a+b\right)\left(a-b\right)^2+\left(b+c\right)\left(b-c\right)^2+\left(c+a\right)\left(c-a\right)^2\ge0\)*Đúng*
P/s: kiểm tra giúp xem em có tính sai chỗ nào ko nha! Dạo hay em hay nhầm lẫn lắm:(
TT
0
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\(\left(x^2+1\right)^2+3x\left(x^2+1\right)+2x^2=0\)
\(\left(x^4+2x^2+1\right)+3x^3+3x+2x^2=0\)
\(x^4+2x^2+1+3x^3+3x+2x^2=0\)
\(x^4+4x^2+1+3x^3+3x=0\)
\(\left(x+1\right)\left(x^3+2x^2+2x+1\right)=0\)
\(\left(x+1\right)\left(x+1\right)\left(x^2+x+1\right)=0\)
\(\orbr{\begin{cases}x+1=0\Rightarrow x=\left(-1\right)\\x^2+x+1=0\left(vôlí\right)\end{cases}}\)
x= -1
\(\left(x^2+1\right)^2+3x\left(x^2+1\right)+2x^2=0\)
\(\Leftrightarrow\left(x^2+1\right)^2+x\left(x^2+1\right)+2x\left(x^2+1\right)+2x^2=0\)
\(\Leftrightarrow\left(x^2+1\right)\left(x^2+x+1\right)+2x\left(x^2+x+1\right)=0\)
\(\Leftrightarrow\left(x^2+2x+1\right)\left(x^2+x+1\right)=0\Leftrightarrow\left(x+1\right)^2\left(x^2+x+1\right)=0\Rightarrow x=-1\)