\(\left(4+8+12+16\right)\cdot\left(x-3\right)=2592\)

\(\Rightarrow\left[\left(4+16\right)+\left(8+12\right)\right]\left(x-3\right)=2592\)

\(\Rightarrow\left(20+20\right)\left(x-3\right)=2592\)

\(\Rightarrow40\left(x-3\right)=2592\)

\(\Rightarrow x-3=\dfrac{2592}{40}\)

\(\Rightarrow x-3=64,8\)

\(\Rightarrow x=64,8+3\)

\(\Rightarrow x=67,8\)

\(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)

\(\Rightarrow\left[\left(x:3+17\right):10+3\cdot2^4\right]:10=10-5\)

\(\Rightarrow\left[\left(x:3+17\right):10+3\cdot16\right]:10=5\)

\(\Rightarrow\left(x:3+17\right)+48=5\cdot10\)

\(\Rightarrow\left(x:3+17\right)+48=50\)

\(\Rightarrow x:3+17=50-48\)

\(\Rightarrow x:3+17=2\)

\(\Rightarrow x:3=2-17\)

\(\Rightarrow x:3=-15\)

\(\Rightarrow x=-15\cdot3\)

\(\Rightarrow x=-45\)

10 - {[(\(x\): 3 + 17): 10 + 3.2⁴] : 10} = 5

       [(\(x\): 3 + 17):10 + 3.16]: 10 = 10 - 5

       [(\(x:3\) + 17): 10 + 48]: 10 = 5

       (\(x\) : 3 + 17): 10 + 48         = 5 x 10

       (\(x\): 3  + 17): 10                  = 50 - 48

       (\(x\) : 3 + 17): 10                   = 2

        \(x\) : 3  + 17 = 2.10

        \(x\): 3  + 17  = 20

        \(x\): 3           = 20 - 17

        \(x\): 3           = 3

        \(x\)                = 3.3

        \(x\)                = 9

Vậy \(x\)                 = 9

A = -5²² - {-222 - [-122 - (100 - 5²²) + 2022]} 

A = -5²² - {-222 - [ -122 - 100 + 5²²) + 2022]}

A = -5²² - {-222 + 122 + 100 - 5²² + 2022}

A = -5²²  + 222 - 122 - 100 + 5²² -2022

A = (-5²² + 5²²) + (222 - 122 - 100) - 2022

A = 0 + (100 - 100) - 2022

A = 0 - 2022

A = -2022

Bạn xem lại đề nhé.

Khối lượng 4 quả chuối là:

\(\dfrac{1}{10}\cdot4=\dfrac{4}{10}\left(kg\right)\)

Khối lượng khay đựng là:

\(\dfrac{5}{4}-\dfrac{4}{10}-\dfrac{1}{8}-\dfrac{1}{3}=\dfrac{47}{120}\left(kg\right)\)

Đáp số: \(\dfrac{47}{120}kg\)

Khối lượng của 4 quả chuối là:

\(\dfrac{1}{10}\times4=\dfrac{4}{10}=\dfrac{2}{5}\left(kg\right)\)

Khối lượng của khay đựng đó là:

\(\dfrac{5}{4}-\dfrac{2}{5}-\dfrac{1}{8}-\dfrac{1}{3}=\dfrac{150}{120}-\dfrac{48}{120}-\dfrac{15}{120}-\dfrac{40}{120}=\dfrac{47}{120}\left(kg\right)\)

Đáp số: \(\dfrac{47}{120}kg\)

`1+2+3+...+x=36`

`⇒ [(x-1):1+1]×(x+1):2=36`

`⇒ (x-1+1)×(x+1):2=36`

`⇒x×(x+1)=36×2`

`⇒x^2+x=72`

`⇒x^2+x-72=0`

`⇒x^2-8x+9x-72=0`

`⇒x(x-8) + 9(x-8)=0`

`⇒(x-8)(x+9)=0`

TH1: `x-8=0`

`⇒x=8`

TH2: `x+9=0`

`⇒x=-9`

Vậy: ....

bn nói cụ thể hơn nha 

 X là số mấy bn ko ghi ra là số mấy thì bọn mình làm sao biết mà giải đc

a) \(\left(1+\dfrac{1}{10}\right)\cdot\left(1+\dfrac{1}{11}\right)\cdot\left(1+\dfrac{1}{12}\right)\cdot...\cdot\left(1+\dfrac{1}{119}\right)\cdot\left(1+\dfrac{1}{120}\right)\)

\(=\dfrac{11}{10}\cdot\dfrac{12}{11}\cdot\dfrac{13}{12}\cdot...\cdot\dfrac{120}{119}\cdot\dfrac{121}{120}\)

\(=\dfrac{11\cdot12\cdot13\cdot...\cdot120\cdot121}{10\cdot11\cdot12\cdot...\cdot119\cdot120}\)

\(=\dfrac{121}{10}\)

b) \(\left(1+\dfrac{2}{5}\right)\cdot\left(1+\dfrac{2}{7}\right)\cdot\left(1+\dfrac{2}{9}\right)\cdot...\cdot\left(1+\dfrac{2}{97}\right)\cdot\left(1+\dfrac{2}{99}\right)\)

\(=\dfrac{7}{5}\cdot\dfrac{9}{7}\cdot\dfrac{11}{9}\cdot...\cdot\dfrac{99}{97}\cdot\dfrac{101}{99}\)

\(=\dfrac{7\cdot9\cdot11\cdot...\cdot99\cdot101}{5\cdot7\cdot9\cdot...\cdot97\cdot99}\)

\(=\dfrac{101}{5}\)

b) \(B=\dfrac{7}{2\cdot5}+\dfrac{7}{5\cdot8}+...+\dfrac{7}{26\cdot29}\)

\(B=7\cdot\left(\dfrac{1}{2\cdot5}+\dfrac{1}{5\cdot8}+...+\dfrac{7}{26\cdot29}\right)\)

\(B=\dfrac{7}{3}\cdot\left(\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+...+\dfrac{3}{26\cdot29}\right)\)

\(B=\dfrac{7}{3}\cdot\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{26}-\dfrac{1}{29}\right)\)

\(B=\dfrac{7}{3}\cdot\left(\dfrac{1}{2}-\dfrac{1}{29}\right)\)

\(B=\dfrac{7}{3}\cdot\dfrac{27}{58}\)

\(B=\dfrac{63}{58}\)