\(-2^{300}=\left(-2^3\right)^{100}=-8^{100}\)

\(-3^{200}=\left(-3^2\right)^{100}=-9^{100}\)

Vì \(-8^{100}>-9^{100}\)nên \(-2^{300}>-3^{200}\)

TL

\(-2^{300}=\left(-2^3\right)^{100}\)=\(-8^{100}\)

\(-3^{200}=\left(-3^2\right)^{100}\)= \(-9^{100}\)

\(-8^{100}>-9^{100}\)(do cái này là số nguyên âm nên cái có GTTĐ lớn hơn sẽ nhỏ hơn)

=>\(-2^{300}>-3^{200}\)

\(75:\left(x+18\right)=52\)

\(\Leftrightarrow x+18=\frac{75}{52}\)

\(\Leftrightarrow x=\frac{75}{52}-18\)

\(\Leftrightarrow x=-\frac{861}{52}\)

Linh đã tiêu được 80.000k còn lại 120.000k nha bạn

Bạn Thế Anh viết nhầm đ sang k rồi nhưng kết quả đúng

Là 120k( 120 000 đ)

Sau 10p, lượng nước đã chiến số phần bể là:

10 : 40 =1/4 

Vậy....

1/4 nha bạn

15 phút=1/4h

90 phút=3/2h

 15 phút = 1/4 giờ và 90 phút = 3/2 giờ

Bạn tham khảo nha

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có mẫu dương pk ko

Nếu là mẫu dương thì:

\(\frac{8}{-11}=\frac{-8}{11}\)

\(\frac{-5}{-9}=\frac{5}{9}\)

\(\frac{8}{-11}\)= \(\frac{-8}{11}\)= \(-\frac{8}{11}\)

\(\frac{-5}{-9}\)= \(\frac{5}{9}\)