Tìm x, y, z: x/3=y/5; y/3=z/2 và x+y-z=28 ?
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Áp dụng dãy tỉ số bằng nhau ta có:
\(\frac{x}{4}=\frac{x}{3}=\frac{z}{9}=\frac{x-3y+4z}{4-3.3+4.9}=\frac{62}{31}=2\)
\(\frac{x}{4}=2\Rightarrow x=2.4=8\)
\(\frac{y}{3}=4\Rightarrow y=3.4=12\)
\(\frac{z}{9}=4\Rightarrow z=4.9=36\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{4}=\frac{y}{3}=\frac{z}{9}=\frac{x-3y+4z}{4-9+36}=\frac{62}{31}=2\)
\(x=9;y=6;z=18\)
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You’ll have (wait) ……to.wait......till he stops (talk) ……talking………….
It’s no use (try) …trying…………….. (interrupt)(ngắt lời) ……to interrupt……… him. You’ll have (wait) to wait
till he stops (talk) talking.
Hc tốt
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ta có :
\(\left(-\frac{7}{5}\right)^n:\left(-\frac{7}{5}\right)^{n-1}=\left(-\frac{7}{5}\right)^{n-\left(n-1\right)}=\left(-\frac{7}{5}\right)^1=-\frac{7}{5}\)
\(\left(-\frac{1}{3}\right)^{2n}:\left(-\frac{1}{3}\right)^n=\left(-\frac{1}{3}\right)^{2n-n}=\left(-\frac{1}{3}\right)^n\)
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a)\(\frac{2}{3}x=-\frac{4}{27}\)
\(\Leftrightarrow x=-\frac{4}{27}:\frac{2}{3}\)
\(\Leftrightarrow x=-\frac{2}{9}\)
b)\(-1\frac{3}{5}x=1\frac{1}{15}\)
\(\Leftrightarrow-\frac{2}{5}x=\frac{16}{15}\)
\(\Leftrightarrow x=-\frac{8}{3}\)
#H
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\(C=\frac{-3}{5}.\frac{0,2}{1,35}.\frac{-0,007}{1,4}.\frac{250}{3}.\frac{27}{10}=\frac{-3}{5}.\frac{20}{135}.\frac{-7}{1400}.\frac{250}{3}.\frac{27}{10}\)
\(=\frac{-2}{5}.\frac{4}{5.9}.\frac{-1}{200}.\frac{250}{3}.\frac{27}{10}=\frac{2.4.250.27}{5.9.5.200.3.10}=\frac{4}{25}\)
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Trả lời :
will see - see - will have graduated
~~Học tốt~~
x =578\(\frac{\hept{\begin{cases}4\\4\\5\end{cases}}}{46}\)nha