tính tổng 1+ 5+9+...+2005+2009
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1 . what about going swimming?
2 . how tall is the Mount Everest ?
Let's go swimming.
=> What about going swimming ?
What's the height of the Mount Everest ?
=> How tall is the Mount Everest ?
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22 . x + 2y = 2013
=> 4 . x + 4 = 2013
=> 4x = 2009
=> x = 502,25
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a)\(\left(x-18\right)=\frac{75}{25}\)
\(x-18=3\)
\(x=21\)
b) \(\left(27x+6\right):3.11=9\)
\(\left(27x+6\right):3=\frac{9}{11}\)
\(\left(27x+6\right)=\frac{27}{11}\)
\(27x=\frac{27}{11}-6=-\frac{39}{11}\)
\(x=-\frac{39}{11}:27=-\frac{39}{297}=-\frac{13}{99}\)
c) \(\left(15-6x\right).3^5=3^6\)
\(15-6x=3^6:3^5=3\)
\(15-3=6x\)
\(12=6x=>x=2\)
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\(3^2.\left(3x-2\right)=2^3\)
\(9.\left(3x-2\right)=8\)
\(27x-18=8\)
\(27x=26\)
\(x=\frac{26}{27}\)
\(3^2.\left(3x-2\right)=2^3\)
\(\Rightarrow\) \(9.\left(3x-2\right)=8\)
\(\Rightarrow\) \(3x-2=\frac{8}{9}\)
\(\Rightarrow\) \(3x=\frac{26}{9}\)
\(\Rightarrow\) \(x=\frac{26}{27}\)
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\(1+4+4^2+4^3+.....+4^{2018}\)
\(=\left(1+4+4^2\right)+\left(4^3+4^4+4^5\right)+....+\left(4^{2016}+4^{2017}+4^{2018}\right)\)
\(=21+\left[4^3\left(1+4+4^2\right)\right]+....+\left[4^{2016}\left(1+4+4^2\right)\right]\)
\(=21+4^3\cdot21+....+4^{2016}\cdot21\)
\(=21\left(1+4^3+....+4^{2016}\right)\)
\(\Rightarrowđpcm\)
Đặt
\(S=1+5+9+....+2005+2009\)
\(taco:S=\frac{\left[\left(2009-1\right):4+1\right].\left(2009+1\right)}{2}\)
\(S=\frac{503.2010}{2}\)
\(S=505515\)
505515
ket
ban
nha