tim x
(x-1)(3x-7)=(x-1)(x+3)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Answer:
\(2x^3+4x^2y+2xy^2\)
\(= 2 x ( x ² + 2 x y + y ² )\)
\(= 2 x ( x + y ) ² \)
\( − 3 x ^4 y − 6 x ^3 y ^2 − 3 x ^2 y ^3 \)
\(=-3x^2y(x^2+2xy+y^2)\)
\(=-3x^2y(x+y)^2\)
\(4x^5y^2+8x^4y^3+4x^3y^4\)
\(=4x^3y^2.x^2+4x^3y^2.2xy+4x^3y^2.y^2\)
\(=4x^3y^2.(x^2+2xy+y^2)\)
\(=4x^3y^2.(x+y)^2\)
\(A=\left(9y^2-6xy+12y\right)+4x^2-16x+2012\)
\(=\left[\left(3y\right)^2-2.3y\left(x-2\right)+\left(x-2\right)^2\right]-\left(x-2\right)^2+4x^2-16x+2012\)
\(=\left(3y-x+2\right)^2+3x^2-12x+2008\)
\(=\left(3y-x+2\right)^2+3\left(x^2-2.x.2+4\right)-3.4+2008\)
\(=\left(3y-x+2\right)^2+3\left(x-2\right)^2+1996\ge1996\)
Dấu "=" xảy ra <=> \(\hept{\begin{cases}3y-x+2=0\\x-2=0\end{cases}\Leftrightarrow}\hept{\begin{cases}y=0\\x=2\end{cases}}\)
\(x^2-12x=-36\)
\(\Rightarrow x^2-12x+36=-36+36\)
\(\Rightarrow\left(x-6\right)^2=0\)
\(\Rightarrow x-6=0\)
\(\Rightarrow x=6\)
a) chu vi hcn : ( a+b):2
diện tích hcn : axb
b) chu vi hình vuông : c x 4
diện tích hình vuông : c x c
c) chu vi : a + b + c
diện tích : ( a x h ) :2
\(\left(x-1\right)\left(3x-7\right)=\left(x-1\right)\left(x+3\right)\)
\(\Leftrightarrow\left(x+1\right)\left(3x-7\right)-\left(x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(\left(3x-7\right)-\left(x+3\right)\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(3x-7-x-3\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(2x-10\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=0\\2x-10=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=5\end{cases}}\)
(x-1)(3X-7)=(x-1)(x+3)
=>(x-1)(3x-7)-(x-1)(x+3)=0
=>(x-1)(3x-7-x-3)=0
=>(x-1)(2x-10)=0
=> + x-1=0 =>x=1
+ 2x-10=0 =>x=5