-4/9 . x = -2/7 : 4/21
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\(a.BC\left(3\cdot5^2;5^2\cdot7\right)\\ =B\left(3\cdot5^2\cdot7\right)\\ =B\left(525\right)=\left\{0;525;1050;...\right\}\\ b.ƯC\left(2^2\cdot3\cdot5;3^2\cdot7;3\cdot5\cdot11\right)\\ =Ư\left(3\right)=\left\{1;3\right\}\)
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\(\dfrac{3}{7}\cdot x=-\dfrac{1}{3}:\dfrac{2}{9}\\ \dfrac{3}{7}\cdot x=-\dfrac{1}{3}\cdot\dfrac{9}{2}\\ \dfrac{3}{7}\cdot x=-\dfrac{3}{2}\\ x=-\dfrac{3}{2}:\dfrac{3}{7}\\ x=-\dfrac{7}{2}\)
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`3/7x = -1/3 : 2/9`
`=> 3/7x = -1/3 . 9/2`
`=> 3/7 x = -3/2`
`=> x = -3/2 . 7/3`
`=> x = -7/2`
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\(\dfrac{5}{21}\cdot\dfrac{-3}{22}-\left(-\dfrac{4}{21}\right)+\dfrac{5}{21}\cdot\dfrac{-19}{22}\\ =\dfrac{5}{21}\cdot\left(-\dfrac{3}{22}-\dfrac{19}{22}\right)+\dfrac{4}{21}\\ =\dfrac{5}{21}\cdot\dfrac{-22}{22}+\dfrac{4}{21}\\ =\dfrac{-5}{21}+\dfrac{4}{21}\\ =\dfrac{-1}{21}\)
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`5/13 + 2/7 + 8/13 - 3/14`
`= (5/13 + 8/13) + (2/7 - 3/14)`
`= 13/13 + 1/14`
`= 1 + 1/14 `
`= 15/14`
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1.did you see, saw
2.does not take, takes
3.did she write, wrote
1 did you see - saw
2 didn't take - took
3 did she give - gave
\(\dfrac{-4}{9}\cdot x=\dfrac{-2}{7}:\dfrac{4}{21}\\ -\dfrac{4}{9}\cdot x=\dfrac{-2}{7}\cdot\dfrac{21}{4}\\ -\dfrac{4}{9}\cdot x=\dfrac{-3}{2}\\ x=-\dfrac{3}{2}:\dfrac{-4}{9}\\ x=\dfrac{3}{2}\cdot\dfrac{9}{4}\\ x=\dfrac{27}{8}\)
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