9-(-11)=bằng bao nhiêu
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TL
119 - x + 6 = 102
x = 23
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2448 :{119-(x-6)}=24
<=>119-(x-6)=2448:24
<=>119-x+6=102
<=>125-x=102
<=>x=125-102
<=>x=23
Vậy x=23
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x-(-7)=-24-4
x-(-7)=(-24)+(-4)
x-(-7)=(-28)
x=(-28)+(-7)
x=(-35)
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( 38 - 29 + 43 ) - ( 43 + 38 )
=38-29+43-43-38
=(43-43)+(38-38)-29
=0+0-29
=-29
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\(S=7^0+7^1+7^2+...+7^{60}\)
\(=1+\left(7^1+7^2\right)+\left(7^3+7^4\right)+...+\left(7^{59}+7^{60}\right)\)
\(=1+7\left(1+7\right)+7^3\left(1+7\right)+...+7^{59}\left(1+7\right)\)
\(=1+8\left(7+7^3+...+7^{59}\right)\)
Suy ra \(S-1=8\left(7+7^3+...+7^{59}\right)⋮8\).
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\(n^2+3n+1=n^2+n+2n+2-1=\left(n+2\right)\left(n+1\right)-1⋮\left(n+1\right)\)
\(\Leftrightarrow1⋮\left(n+1\right)\Leftrightarrow n+1\inƯ\left(1\right)=\left\{-1,1\right\}\)
\(\Leftrightarrow n\in\left\{-2,0\right\}\).
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hình tam giác đều : 3 cạnh bằng nhau , 3 góc bằng nhau ,mỗi góc bằng 60 độ
-20 nha
TL:
9-(-11)=9+11=20
HT