ai làm đúng mình vote cho

bài thơ của tác giả nào ạ? nếu không có tác giả thì bạn viết thơ ra để mình làm ạ

1. There are some books on the table.

2. We went to the party yesterday.

3. He is growing vegetables in the garden now.

4. She is helping her parents in the kitchen at present.

5. I stayed at home yesterday because I looked after my little sister.

1 There are some books on the table 

2 We went to the party yesterday

3 He is growing vegetables in the garden now

4 She is helping her parents in the kitchen at present

5 I stayed at home yesterday because I looked after my little sister

`5^2 . 11 + 5^2 . 19`

`= 5^2 . (11+19)`

`= 25 . 30`

`= 750`

2020

2020

\(m.\left(\dfrac{14}{3}+\dfrac{14}{15}+...+\dfrac{14}{195}\right)=1\)

=> \(m.7.\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+...+\dfrac{2}{13.15}\right)=1\)

=> \(7m.\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{13}-\dfrac{1}{15}\right)=1\)

=> \(7m.\left(1-\dfrac{1}{15}\right)=1\)

=> \(\dfrac{7m.14}{15}=1\)

=> \(m=\dfrac{15}{98}\)

`3^3 - 2^2 . 5 + 125 : 5`

`= 27 - 4 . 5 +` \(\dfrac{125}{52}\)

`= 27 - 20 +` \(\dfrac{125}{52}\)

`= 7 +` \(\dfrac{125}{52}\)

`=` \(\dfrac{7.52+125}{52}\)

`=` \(\dfrac{489}{52}\)

\(3^3-2^2\cdot5+125:52\)

= \(27-4\cdot5+\dfrac{125}{52}\)

= \(27-20+\dfrac{125}{52}\)

= \(7+\dfrac{125}{52}\)

= \(\dfrac{52\cdot7+125}{52}\)

= \(\dfrac{489}{52}\)

`(x + 7) - 25 = 13`

`=> x +7 = 13 + 25`

`=> x+ 7 = 38`

`=> x = 38 - 7`

`=> x = 31`

Vậy `x=31`

\(\left(x+7\right)-25=13\)

\(x+7=13+25\)

\(x+7=38\)

\(x=38-7\)

\(x=31\)

vậy x = 31

`(7x - 11)^3 = 2^5 . 5^2 + 100`

`=> (7x - 11)^3 = 32 . 25 + 100`

`=> (7x - 11)^3 = 800 + 100`

`=> (7x - 11)^3 = 900`

`=> 7x - 11 =` \(\sqrt[3]{900}\)

`=> 7x = 11 +` \(\sqrt[3]{900}\)

`=> x =` \(\dfrac{11+\sqrt[3]{900}}{7}\)

Vậy ...

Sửa đề:

\(\left(7x-11\right)^2=2^5.5^2+100\)

\(\left(7x-11\right)^2=32.25+100\)

\(\left(7x-11\right)^2=800+100\)

\(\left(7x-11\right)^2=900\)

\(\left(7x-11\right)^2=30^2\)

\(\Rightarrow7x-11=30\)

\(7x=30+11\)

\(7x=41\)

\(x=41\div7\)

\(x=\dfrac{41}{7}\)

Vậy \(x=\dfrac{41}{7}\)

\(\left(\dfrac{7}{30}\right)-\left(\dfrac{11}{36}\right)+\left(\dfrac{23}{30}\right)-\left(\dfrac{25}{36}\right)\)

\(=\dfrac{7}{30}+\dfrac{23}{30}-\left(\dfrac{11}{36}+\dfrac{25}{36}\right)\)

\(=\dfrac{30}{30}-\dfrac{36}{36}\)

\(=1-1\)

\(=0\)

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