1/2+5/6+11/12+19/20+29/30+41/42+55/56
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45/60 = (45 : 15)/(60 : 15) = 3/4
9/30 = (9 : 3)/(30 : 3) = 3/10
21/42 = (21 : 21)/(42 : 21) = 1/2
\(6:\dfrac{4}{6}=6\cdot\dfrac{6}{4}=\dfrac{6\cdot6}{4}=\dfrac{36}{4}=9\)
Lời giải:
Theo bài ra ta có:
$\frac{43-m}{36}=\frac{5}{12}$
$43-m=\frac{5}{12}\times 36=15$
$m=43-15$
$m=28$
Vậy số cần tìm là $28$.
TK
1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90
1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90
9 – (1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90)
9 – [1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+1/(5x6)+1/(6x7)+1/(7x8)+1/(8x9)+1/(9x10)]
9 – ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)
9 – (1 – 1/10) = 9 – 9/10 = 81/10
A = \(\dfrac{1}{2}\) + \(\dfrac{5}{6}\) + \(\dfrac{11}{12}\) + \(\dfrac{19}{20}\) + \(\dfrac{29}{30}\) + \(\dfrac{41}{42}\) + \(\dfrac{55}{56}\)
A = 1 - \(\dfrac{1}{2}\) + 1 - \(\dfrac{5}{6}\) + 1 - \(\dfrac{1}{12}\) + 1 - \(\dfrac{1}{20}\) + 1 - \(\dfrac{1}{30}\) + 1 - \(\dfrac{1}{42}\) + 1 - \(\dfrac{1}{56}\)
A 1 x 7 - (\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{56}\))
A = 7- (\(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}\))
A = 7 - (1 - \(\dfrac{1}{8}\))
A = 7 - \(\dfrac{7}{8}\)
A = \(\dfrac{49}{8}\)