2| \(\overrightarrow{MA}\)+ \(\overrightarrow{MB}+\overrightarrow{MC}\)| = \(3\left|\overrightarrow{MB}+\overrightarrow{MC}\right|\)
B, \(\left|3\overrightarrow{MA}-2\overrightarrow{MB}+\overrightarrow{MC}\right|\)= \(\left|\overrightarrow{MB}-\overrightarrow{MC}\right|\)
TÌM {M}
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