\(\dfrac{24}{5}+\left(12-\dfrac{24}{5}\right)\times\dfrac{3}{8}\)

\(=\dfrac{24}{5}+\dfrac{36}{5}\times\dfrac{3}{8}\)

\(=\dfrac{24}{5}+\dfrac{108}{40}\)

\(=\dfrac{192+108}{40}=\dfrac{300}{40}=7,5\)

289000x15%+289000

Số tiền đôi giày bán trước khi giảm giá:

289000+(100%+15%)= 289115 đồng

2/3 số cam sau lần 1 còn lại là 29+1=30(quả)

Số cam sau lần 1 còn lại là 30:2/3=45(quả)

2/3 số cam ban đầu là 45+1=46(quả)

Số cam lúc đầu là \(46:\dfrac{2}{3}=46\cdot\dfrac{3}{2}=69\left(quả\right)\)

\(B=1+\dfrac{1}{3}+\dfrac{1}{6}+...+\dfrac{1}{1275}\)

\(=\dfrac{2}{2}+\dfrac{2}{6}+\dfrac{2}{12}+...+\dfrac{2}{2550}\)

\(=2\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{2550}\right)\)

\(=2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{49}-\dfrac{1}{50}\right)\)

\(=2\cdot\left(1-\dfrac{1}{50}\right)=2-\dfrac{2}{50}< 2\)

?

  7/8 - 3/8 . ( 1 - 2/3)

= 7/8 - 3/8 . 1/3

= 7/8 - 1/8

= 6/8.

6/8

\(A\left(x\right)=x^2+2x+2\)

\(=x^2+2x+1+1\)

\(=\left(x+1\right)^2+1>=1>0\forall x\)
=>A(x) không có nghiệm

3/5

 13/5 - 2

= 3/5.

a: \(M\left(x\right)=3x^4-5x^2-2x^3-4x+6x^2+8x^3-2\)

\(=3x^4+\left(-2x^3+8x^3\right)+\left(6x^2-5x^2\right)-4x-2\)

\(=3x^4+6x^3+x^2-4x-2\)

\(N\left(x\right)=\sqrt{2}x^4+\dfrac{1}{2}x^2-3x^3-\sqrt{2}x^4+5x^3-\dfrac{3}{2}x^2-4x-3\)

\(=\left(\sqrt{2}x^4-\sqrt{2}x^4\right)+\left(-3x^3+5x^3\right)+\left(\dfrac{1}{2}x^2-\dfrac{3}{2}x^2\right)-4x-3\)

\(=2x^3-x^2-4x-3\)

b: G(x)=M(x)+N(x)

\(=3x^4+6x^3+x^2-4x-2+2x^4-x^2-4x-3\)

\(=5x^4+6x^3-8x-5\)

c: H(x)=M(x)-N(x)

\(=3x^4+6x^3+x^2-4x-2-2x^4+x^2+4x+3\)

\(=x^4+6x^3+2x^2+1\)

11/3 x 8/15 + 11/3 x 7/15

= 11/3 x (8/15 + 7/15)

= 11/3 x 1

= 11/3

123+123=642