Tìm x thuộc số tự nhiên:
(x - 5)5 = (x - 5)15
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`Answer:`
\(S=1+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{61}+\frac{1}{62}+\frac{1}{63}\)
\(=\frac{1}{5}+\left(\frac{1}{13}+\frac{1}{14}+\frac{1}{15}\right)+\left(\frac{1}{61}+\frac{1}{62}+\frac{1}{63}\right)\)
Ta thấy:
\(\frac{1}{13}< \frac{1}{12}\)
\(\frac{1}{14}< \frac{1}{12}\)
\(\frac{1}{15}< \frac{1}{12}\)
\(\Rightarrow\frac{1}{13}+\frac{1}{14}+\frac{1}{15}< \frac{1}{12}+\frac{1}{12}+\frac{1}{12}\)
\(\Rightarrow\frac{1}{13}+\frac{1}{14}+\frac{1}{15}< \frac{1}{4}\text{(*)}\)
Ta thấy:
\(\frac{1}{61}< \frac{1}{60}\)
\(\frac{1}{62}< \frac{1}{60}\)
\(\frac{1}{63}< \frac{1}{60}\)
\(\Rightarrow\frac{1}{61}+\frac{1}{62}+\frac{1}{63}< \frac{1}{60}+\frac{1}{60}+\frac{1}{60}\)
\(\Rightarrow\frac{1}{61}+\frac{1}{62}+\frac{1}{63}< \frac{1}{20}\text{(**)}\)
Từ (*)(**)\(\Rightarrow S=\frac{1}{5}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{61}+\frac{1}{62}+\frac{1}{63}< \frac{1}{5}+\frac{1}{4}+\frac{1}{20}\)
\(\Rightarrow S=\frac{1}{5}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{61}+\frac{1}{62}+\frac{1}{63}< \frac{1}{2}\)
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`Answer:`
\(\left(x-5\right)^5=\left(x-5\right)^{15}\)
\(\Leftrightarrow\left(x-5\right)^5=\left(x-5\right)^{10}.\left(x-5\right)^5\)
\(\Leftrightarrow\left(x-5\right)^{10}=1\)
\(\Leftrightarrow x-5=1\)
\(\Leftrightarrow x=6\)
`Answer:`
Bạn bổ sung thêm trường hợp `x-5=-1<=>x=4` giúp mình nhé.