Đổi 10cm= 1dm

Cạnh đáy bể:

20:4=5(dm)

Diện tích đáy bể:

5 x 5 = 25(dm²)

Thể tích viên đá:

25 x 1= 25(dm³)

Đ.số:25 dm³

2x-x⁰=3⁵:3³=3²=9

=>2x-1=9

=>2x=9+1=10

=>x=10:2=5.

\(2x-x^0=3^5:3^3\\ 2x-1=3^{5-3}\\ 2x-1=3^2\\ 2x-1=9\\ 2x=9+1\\ 2x=10\\ x=\dfrac{10}{2}\\ x=5\)

Bài này mới ra mà bạn? vậy chắc bạn chờ một tí rồi thử lại xem nhé.

Đó là bài của bộ sách nào vậy em, em nói cụ thể ra thì cô mới test được

\(\dfrac{28^7.5^8.15^9}{14^8.25^9.6^{12}}=\dfrac{2^7.14^7.5^8.5^9.3^9}{14^7.14.\left(5^2\right)^9.3^{12}.2^{12}}\\ =\dfrac{14^7.5^{17}.3^9.2^7}{14^7.14.5^{17}.5.3^9.3^3.2^7.2^5}\\ =\dfrac{1}{14.5.3^3.2^5}=\dfrac{1}{14.5.27.32}\\ =\dfrac{1}{60480}\)

\(\dfrac{28^7.5^8.15^9}{14^8.25^9.6^{12}}\\ =\dfrac{2^7.14^7.5^8.5^9.3^9}{14^8.5^9.5^9.3^{12}.2^{12}}\\ =\dfrac{1}{14.5.3^3.2^5}\\ =\dfrac{1}{60480}\)

16⁵+2¹⁵=(2⁴)⁵+2¹⁵=2²⁰+2¹⁵=2¹⁵(1+2⁵)=2¹⁵x33⋮33

=>ĐPCM

Ok e

a) \(3^{54}\)

\(2^{200}=4^{100}>3^{54}\)

\(\Rightarrow3^{54}< 2^{200}\)

b) \(15^{12}=3^{12}.5^{12}\)

\(1^3.125^3=\left(5^3\right)^3=5^9< 3^{12}.5^{12}\)

\(\Rightarrow15^{12}>1^3.125^3\)

c) \(78^{12}-78^{11}=78^{11}.\left(7-1\right)=78^{11}.6\)

\(78^{11}-78^{10}=78^{10}.\left(7-6\right)=78^{10}.6< 78^{11}.6\)

\(\Rightarrow78^{12}-78^{11}>78^{11}-78^{10}\)

d) \(72^{45}-72^{44}=72^{44}.\left(72-1\right)=72^{44}.72>27^{44}\)

\(\Rightarrow72^{45}-72^{44}>27^{44}\)

e) \(3^{39}=\left(3^3\right)^{13}=27^{13}>11^{11}\)

\(\Rightarrow3^{39}>11^{11}\)

Giải chi tiết dùm mik nhé.

1. ours->our

2. its their->they're their

3. my's->mine

4. he's->his

5. your->yours

6. mine->me

7. they're->their

8. dog water->dog's water

So sánh

\(A=\dfrac{1999^{1999}+1}{1999^{1998}+1}\) ; \(B=\dfrac{1999^{2000}+1}{1999^{1999}+1}\)

Ta có: \(B=\dfrac{1999^{2000}+1}{1999^{1999}+1}>1\) ( vì tử > mẫu )

Do đó: \(B=\dfrac{1999^{2000}+1}{1999^{1999}+1}>\dfrac{1999^{2000}+1+1998}{1999^{1999}+1+1998}=\dfrac{1999^{2000}+1999}{1999^{1999}+1999}=\dfrac{1999.\left(1999^{1999}+1\right)}{1999.\left(1999^{1998}+1\right)}=\dfrac{1999^{1999}+1}{1999^{1998}+1}=A\)

Vậy B > A

Chúc bạn học tốt

\(B=1\cdot2\cdot3+2\cdot3\cdot4+3\cdot4\cdot5+...+98\cdot99\cdot100\)

\(\Rightarrow4B=4\cdot\left(1\cdot2\cdot3+2\cdot3\cdot4+...+98\cdot99\cdot100\right)\)

\(\Rightarrow4B=1\cdot2\cdot3\cdot\left(4-0\right)+2\cdot3\cdot4\cdot\left(5-1\right)+3\cdot4\cdot5\cdot\left(6-2\right)+...+98\cdot99\cdot100\cdot\left(101-97\right)\)

\(\Rightarrow4B=1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot5-1\cdot2\cdot3\cdot4-....+98\cdot99\cdot100\cdot101-97\cdot98\cdot99\cdot100\)

\(\Rightarrow4B=98\cdot99\cdot100\cdot101\)

\(\Rightarrow B=\dfrac{98\cdot99\cdot100\cdot101}{4}\)

\(\Rightarrow B=25\cdot98\cdot99\cdot101\)

B=1x2x3+2x3x4+...+98x99x100

=>4B=1x2x3x(4-0)+2x3x4x(5-1)+...+98x99x100x(101-97)

4B=1x2x3x4+2x3x4x5-1x2x3x4+...+98x99x100x101-97x98x99x100

4B=98x99x100x101

=>B=\(\dfrac{98\cdot99\cdot100\cdot101}{4}\)=24497550.

Có ai giải được câu này không?

ko khó lắm