Đặt \(\left(x+c\right)\left(x^2-x+1\right)=x^3+ax^2+bx+6\)

\(x^3-x^2+x+cx^2-cx+c=x^3+ax^2+bx+6\)

\(x^3+x^2\left(c-1\right)+x\left(1-c\right)+c=x^3+ax^2+bx+6\)

Áp dụng phương pháp đồng nhất hệ số ta có:

\(\hept{\begin{cases}c-1=a\\1-c=b\\c=6\end{cases}}\Leftrightarrow\hept{\begin{cases}a=5\\b=-5\\c=6\end{cases}}\left(Th\text{ỏa}m\text{ãn}\right)\)

Vậy \(a=5;b=-5\)

Tham khảo nhé~

Put the verbs in brackets into the simple present or the present progressive tense.

1. Cuckoos (not build)...don't build...........nests. They (use).....use....... the nests of other birds.

2. You can see Tom now. He (have) .....is having..... a bath.

3. He usually (drink).....drinks...... coffee but today he (drink)....drinks...... tea.

4. Ann (make)....is making....... a dress for herself at the moment. She (make)........makes..... all her own clothes.

5. I (wear)......wear..... my sunglasses today because the sun is very strong.

6. The kettle ( boil).......is boiling....now. Shall I make the tea.

1. don't build            -          use

2.is having

3. drinks        -        drinks

4. is making             -           makes

5. wear

6. is boiling

P/s tham khảo nha

1. \(\Delta AFD=\Delta AFH\left(ch-gn\right)\Rightarrow AD=AH=a\)

2. \(\Delta AKH=\Delta AKB\left(ch-cgv\right)\Rightarrow\widehat{KAH}=\widehat{KAB}\) hay \(\widehat{KAE}=\widehat{KAB}\)

AK là tia phân giác của góc BAE

3. \(\Delta AFD=\Delta AFH\left(cmt\right)\Rightarrow FD=FH\)

\(\Delta AKH=\Delta AKB\left(cmt\right)\Rightarrow HK=KB\)

Chu vi tam giác CFK là:

          \(FK+KC+FC=FH+HK+KC+FC=FD+KB+KC+FC=\left(FD+FC\right)+\left(KB+KC\right)=DC+BC=2a\)

Ta có:

\(x^2y^2\left(y-x\right)+y^2z^2\left(z-y\right)-z^2x^2\left(z-x\right)\)

\(=x^2y^2\left(y-x\right)+y^2z^2\left(z-x-y+x\right)-z^2x^2\left(z-x\right)\)

\(=x^2y^2\left(y-x\right)+y^2z^2\left(z-x\right)-y^2z^2\left(y-x\right)-z^2x^2\left(z-x\right)\)

\(=y^2\left(y-x\right)\left(x-z\right)\left(x+z\right)+z^2\left(z-x\right)\left(y-x\right)\left(y+x\right)\)

\(=\left(y-x\right)\left(x-z\right)\left(y^2x+y^2z-z^2y-z^2x\right)\)

\(=\left(y-x\right)\left(x-z\right)\left(y-z\right)\left(xy+yz+zx\right)\)

HOA HOC 

CAI THU NHAT LA 56*2+16*3=160

Theo đề bài t có : A=5/3.B

=>A+B=5/3.B +B=64

=>8/3.B=64

=>B=24

=> A=40

Vậy A là Canxi, kí hiệu Ca

ta co A+B=64

ma A = 5/3B

nen 5/3B+B=64

B(5/3+1)=64

B=64:8/3=24

A=24*5/3=40

suy ra A la canxi

B la magie