hãy tính các tỉ số lượng giác còn lại của góc \(\alpha\),biết:
a)sin\(\alpha\)=0,8
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ĐKXĐ: \(x>0\)
\(P=\left(\frac{1}{x+\sqrt{x}}-\frac{1}{\sqrt{x}+1}\right):\frac{\sqrt{x}}{x+2\sqrt{x}+1}\)
\(=\left(\frac{1}{\sqrt{x}\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}\right).\frac{\left(\sqrt{x}+1\right)^2}{\sqrt{x}}\)
\(=\frac{1-\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}.\frac{\left(\sqrt{x}+1\right)^2}{\sqrt{x}}\)
\(=\frac{\left(1-\sqrt{x}\right)\left(1+\sqrt{x}\right)}{x}\)
\(=\frac{1-x}{x}\)
mik ko bít
I don't now
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\(\Delta ABC\)là tam giác vuông. do \(\sqrt{AB^2+AC^2}=BC\)
a) tìm \(\widehat{C}\)
\(sinC=\frac{AB}{BC}=\frac{10}{26}=\frac{5}{13}\)
\(\Rightarrow\widehat{C}\approx23º\)
Tìm góc B: \(\widehat{B}=90º-\widehat{C}\approx90º-23º\approx67º\)
b) tìm AH
\(AH.BC=AB.AC\)
\(\Leftrightarrow AH.26=10.24\)
\(\Leftrightarrow AH=240:60=4cm\)
có j sai xót mong m.n bỏ qa
mik ko bít
I don't now
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mik ko bít
I don't now
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mik ko bít
I don't now
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A. Bài tập cơ bản:Viết lại các câu, bắt đầu bằng “ I wish”
1. I don’t have to study.
- I wish ………I had to study……………………….……………
2. We had a lot of homework yesterday.
I wish ……………we hadn't had a lot of homework yesterday.………….
3. It rains. .
- I wish …………it didn't rain…………………………….………………………..
4. It was very cold last night. .
- I wish ……………………it hadn't been ery cold last night.……….……..
5. They work slowly. .
- I wish ……………They didn't work slowly.………….…..…………
5. She doesn’t join in the trip. .
- I wish ……………She joined in the trip. . ………………………….……
6. I am not good at English. .
- I wish …………… I were good at English. .………….………
7. He studies badly. .
- I wish …………… He didn't study badly. . ………………………….………………..
8. He doesn’t playing sports. .
- I wish …………………He d playing sports. . …………………….…
9. I don’t have a computer.
- I wish …………I had a computer. …………………..………….………
10. Today isn’t a holiday.
- I wish ………………Today were a holiday……………………….…………
a) sin a=0,8
Ta có: \(\sin^2a+\cos^2a=1\)
\(\Rightarrow\cos^2a=1-\sin^2a=1-0,8^2=0,36\)
\(\Rightarrow\orbr{\begin{cases}\cos a=0,6\\\cos a=-0,6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\tan a=\frac{4}{3}\\\tan a=\frac{-4}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\cot a=\frac{3}{4}\\\cot a=\frac{-3}{4}\end{cases}}\)
\(\sin a=0,8\)
\(\sin^2a=1-\sin^2a=1\)
\(\cos^2a=1-\sin^2a=1-0,8^2=0,36\)
\(\Rightarrow\hept{\begin{cases}\cos a=0,6\\\cos a=-0,6\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}\tan a=\frac{4}{3}\\\tan a=\frac{-4}{3}\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}\cot a=\frac{3}{4}\\\cot a=\frac{-3}{4}\end{cases}}\)
Code : Breacker