\(\frac{x-2}{8x^2-8x}-\frac{x+1}{6x^3-6x^2}=\frac{x-1}{8x\left(x-1\right)}-\frac{x+1}{6x^2\left(x-1\right)}\)

\(=\frac{3x\left(x-1\right)}{24x^2\left(x-1\right)}-\frac{\left(x+1\right)4}{24x^2\left(x-1\right)}=\frac{3x^2-3x-4x-4}{24x^2\left(x-1\right)}\)

\(=\frac{3x^2-7x-4}{24x^2\left(x-1\right)}\)

4x - 4x² - 1 + 81z²

= 81z² - ( 4x² - 4x + 1 )

= ( 9z )² - ( 2x - 1 )²

= [ 9z - ( 2x - 1 ) ][ 9z + ( 2x - 1 ) ]

= ( 9z - 2x + 1 )( 9z + 2x - 1 ) 

\(4x-4x^2-1+81z^2\)

\(=-\left(4x^2-4x+1\right)+81z^2=81z^2-\left(2x-1\right)^2\)

\(=\left(9z-2z+1\right)\left(9z+2z-1\right)\)

\(x\left(x+2\right)+x^2-5x=0\)

\(\Leftrightarrow x^2+2x+x^2-5x=0\)

\(\Leftrightarrow2x^2-3x=0\Leftrightarrow x\left(2x-3\right)=0\)

\(\Leftrightarrow x=0;\frac{3}{2}\)

X(x+2)+ x² -5x= 0

x² +2x +x² - 5x= 0

2x²- 3x= 0

x( 2x-3 )= 0

x= 0 hoặc 2x-3= 0

x=0 hoặc x= 1,5

-3y2 hay là- -3y mũ 2 hay -3y tất cả mũ 2 thế ạ, vs lại bn đánh thiếu 1 cái dấu đóng ngoặc nha ,vị trí đánh ngoặc bn đánh thiếu đặt ở đâu á?

bn đánh đề chữ cho mik vs chứ đề số bn đánh khó hiểu quá

\(\frac{x+4}{x^2-4}-\frac{2}{x^2+2x}\)

\(=\frac{x+4}{\left(x-2\right)\left(x+2\right)}-\frac{2}{x\left(x+2\right)}\)

\(=\frac{\left(x+4\right).x}{x\left(x-2\right)\left(x+2\right)}-\frac{2\left(x-2\right)}{x\left(x-2\right)\left(x+2\right)}\)

\(=\frac{x^2+4x-2x-4}{x\left(x-2\right)\left(x+2\right)}=\frac{x^2+2x-4}{x\left(x-2\right)\left(x+2\right)}\)

\(=\frac{x^2-2^2+2x}{x\left(x-2\right)\left(x+2\right)}=\frac{\left(x+2\right)\left(x-2\right)+2x}{x\left(x-2\right)\left(x+2\right)}=\frac{2x}{x}\)

\(\frac{x+4}{x^2-4}-\frac{2}{x^2+2x}ĐK:x\ne\pm2;0\)

\(=\frac{x+4}{\left(x-2\right)\left(x+2\right)}-\frac{2}{x\left(x+2\right)}=\frac{x\left(x+4\right)}{x\left(x-2\right)\left(x+2\right)}-\frac{2\left(x-2\right)}{x\left(x-2\right)\left(x+2\right)}\)

\(=\frac{x^2+4x-2x+4}{x\left(x-2\right)\left(x+2\right)}=\frac{x^2-2x+4}{x\left(x-2\right)\left(x+2\right)}\)

\(=\frac{\left(x-2\right)^2}{x\left(x-2\right)\left(x+2\right)}=\frac{x-2}{x\left(x+2\right)}\)