giúp mình nhé mai mình phải nộp rồi
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\(x+\frac{3}{5}=\frac{5x+3}{5}\)
\(y-\frac{2}{4}=y-\frac{1}{2}=\frac{2y-1}{2}\)
\(z+\frac{y}{x}=\frac{xz+y}{x}\)
Mà \(x+\frac{3}{5}=y-\frac{2}{4}=z+\frac{y}{x}\)
\(\Rightarrow\frac{5x+3}{5}=\frac{2y-1}{2}=\frac{xz+y}{x}\)
\(\Rightarrow\frac{5x+3}{5}=\frac{2y-1}{2}\)
\(\Leftrightarrow2\left(5x+3\right)=5\left(2y-1\right)\)
\(10x+6=10y-5\)
\(10x+6-10y+5=0\)
\(10\left(x-y\right)+11=0\)
\(x-y=-\frac{11}{10}\)
\(\Rightarrow x=-\frac{11}{10}+y\)
Lại có : \(xy=70\)
\(\Rightarrow-\frac{11}{10}+y.y=70\)
\(y\left(-\frac{11}{10}+1\right)=70\)
\(-\frac{1}{10}y=70\)
\(y=70:\left(-\frac{1}{10}\right)\)
\(y=70.\left(-10\right)\)
\(y=-700\)
\(\Rightarrow x.\left(-700\right)=70\)
\(x=-\frac{1}{10}\)
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\(\frac{5}{2}\left(x-\frac{3}{5}\right)-\frac{1}{10}=x-3\)
\(\frac{5}{2}x-\frac{3}{2}-\frac{1}{10}=x-2\)
\(\frac{5}{2}x-\frac{15}{10}-\frac{1}{10}=x-2\)
\(\frac{5}{2}x-\frac{7}{5}=x-2\)
\(\frac{5}{2}x-\frac{7}{5}-x+2=0\)
\(x\left(\frac{5}{2}-1\right)-\frac{7}{5}+\frac{10}{5}=0\)
\(\frac{3}{2}x+\frac{3}{5}=0\)
\(\frac{3}{2}x=\left(-\frac{3}{5}\right)\)
\(x=\left(-\frac{3}{5}\right):\frac{3}{2}\)
\(x=\left(-\frac{3}{5}\right).\frac{2}{3}\)
\(x=\left(-\frac{2}{5}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9^5.27^3}{3^{18}}\)
\(=\frac{\left(3^2\right)^5.\left(3^3\right)^3}{3^{18}}\)
\(=\frac{3^{10}.3^9}{3^{18}}\)
\(=\frac{3^{19}}{3^{18}}=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có: