\(\dfrac{23}{7}x-\dfrac{1}{8}=\dfrac{11}{4}\)

\(\dfrac{23}{7}x=\dfrac{11}{4}+\dfrac{1}{8}\)

\(\dfrac{23}{7}x=\dfrac{23}{8}\)

\(x=\dfrac{23}{8}\div\dfrac{23}{7}\)

\(x=\dfrac{7}{8}\)

723​x−81​=411​

237�=114+18723​x=411​+81​

237�=238723​x=823​

�=238÷237x=823​÷723​

�=78x=87​
 

\(8x^3-12x^2+6x-1=\left(2x-1\right)^3\)

48 - 2 : x = 16

2 : x = 48 - 16 = 32

x = 2 : 32 = \(\dfrac{2}{32}=\dfrac{1}{16}\)

48-2:x=16

2:x=48-16

2:x=32

X=2:32

X=1/16

\(x^2+x+35=x\left(x+1\right)+35\)

mà \(\left\{{}\begin{matrix}x\left(x+1\right)⋮2\\35⋮̸2\end{matrix}\right.\)

\(\Rightarrow x\left(x+1\right)+35⋮̸2\)

\(\Rightarrow dpcm\)

\(x^2+x+35=x\left(x+1\right)+35\)

mà \(x\left(x+1\right)\) là 2 số liên tiếp nên chia hết cho 2

      35 là số lẻ không chia hết cho 2

\(\Rightarrow x\left(x+1\right)+35\) không chia hết cho 2

\(\Rightarrow dpcm\)

\(28:14:4:2=2:4:2=0,5:2=0,25\)

28:4=7

28:2=14

14:4=3,5

14:2=7

\(\left(x-5\right)^{2020}+\left(y-x+1\right)^{2022}=0\left(1\right)\)

Ta có \(\left\{{}\begin{matrix}\left(x-5\right)^{2020}\ge0,\forall x\\\left(y-x+1\right)^{2022}\ge0,\forall x;y\end{matrix}\right.\)

\(\left(1\right)\Rightarrow\left\{{}\begin{matrix}\left(x-5\right)^{2020}=0\\\left(y-x+1\right)^{2022}=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x-5=0\\y-x+1=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=5\\y-5+1=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=5\\y=4\end{matrix}\right.\)

( 2x - 5 )2020 + ( 5y + 1 )2022 ≤ 0

Ta có : ( 2x - 5 )2020 ≥ 0 ∀ x

            ( 5y + 1 )2022 ≥ 0 ∀ y

=> ( 2x - 5 )2 + ( 5y + 1 )2022 ≥ 0 ∀ x, y

Kết hợp với đề bài => Chỉ xảy ra trường hợp ( 2x - 5 )2020 + ( 5y + 1 )2022 = 0

Khi đó \hept{2�−5=05�+1=0⇔\hept{�=52�=−15\hept{2x−5=05y+1=0​⇔\hept{x=25​y=−51​​
 

\(a.\left[\left(8x-12\right):4\right]\cdot3^3=3^6\\ \left(8x-12\right):4=3^6:3^3\\ \left(8x-12\right):4=27\\ 8x-12=27\cdot4\\ 8x-12=108\\ 8x=108+12\\ 8x=120\\ x=15\\ b.41-2^{x+1}=9\\ 2^{x+1}=32\\ 2^{x+1}=2^5\\=> x+1=5\\ =>x=4\)

a,[(8x-12):4].3³=3⁶

(8x-12):4=3⁶:3³

(8x-12):4=3³

(8x-12):4=9

8x-12=9.4

8x-12=36

8x=36+12

8x=48

x=6

Vậy x=6

b,41-2^x+1=9

2^x+1=41-9

2^x+1=32

2^x+1=2⁵

^x+1=5

^x=5-1

^x=4

^{Vậy x=4}

^{Chúc bạn học tốt:33}

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3. He is such a good boy that everyone loves him.
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