1.That is -> These are

2. among -> between

Answer :

1. That is - that are

2. among - between

1. It weighs 13,760 kilos.

2. The numerals are 61cm high.

3. Yes, it is.

4. It refers to "Talking clock".

Big Ben is in Westminster,next to the House of Parliament in the centre of London.People call the whole clock tower Big Ben but Big Ben is the name of the bell ínside the tower.The bell is very big.It weighs 13,760 kilos.The clock on the tower has got four faces and the numerals are 61 cm high.It is a very accurate clock.When English people want to know the exact time they telephone the "Talking clock".It tells people the time using Big Ben.Be careful,it is very expensive to phone the"Talking clock".

1. How heavy is it?

........It weighs 13,760 kilos..............................

2. How high are the numerals?

.......The numerals are 61 cm high..................................

3. Is Big Ben the most exact clock in London?

.......Yes, it is...................................

4. What does the word "It" refer to?

........The work "It" refers to "Talking clock".......................................

1-The number of time he spends gardening is increasing every day

2-It would be both noed and appreciating if you could finish the work before you leave

3-The suits were hanged in the closet when they were returned from the cleaners

4-A vast quantity of radioactive material is made when a hydfrogen bomb explode

2,could finish=>finished๖²⁴ʱŠїêʉ şαø вóηɠ đá"NCTK"

Xin hỏi cậu học lớp mấy ?

mình học lớp 6

\(S=\frac{5^2}{1.6}+\frac{5^2}{6.11}+...+\frac{5^2}{26.31}\)

\(S=5.\left(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{26.31}\right)\)

\(S=5.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{26}-\frac{1}{31}\right)\)

\(S=5.\left(1-\frac{1}{31}\right)\)

\(S=5.\frac{30}{31}\)

\(S=\frac{150}{31}\)

Câu L bạn thiếu số\(\frac{1}{475}\)

\(L=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+\frac{1}{475}+\frac{1}{775}+\frac{1}{1147}\)

\(L=\frac{1}{1.7}+\frac{1}{7.13}+\frac{1}{13.19}+\frac{1}{19.25}+\frac{1}{25.31}+\frac{1}{31.37}\)

\(L=\frac{1}{6}.\left(\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+\frac{6}{19.25}+\frac{6}{25.31}+\frac{6}{31.37}\right)\)

\(L=\frac{1}{6}.\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+\frac{1}{19}-\frac{1}{25}+\frac{1}{25}-\frac{1}{31}+\frac{1}{31}-\frac{1}{37}\right)\)

\(L=\frac{1}{6}.\left(1-\frac{1}{37}\right)\)

\(L=\frac{1}{6}.\frac{36}{37}\)

\(L=\frac{6}{37}\)

\(S=\frac{5^2}{1.6}+\frac{5^2}{6.11}+...+\frac{5^2}{26.31}\)

\(=5\left[\left(1-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{11}\right)+...+\left(\frac{1}{26}-\frac{1}{31}\right)\right]\)

\(=5\left[1-\frac{1}{31}\right]\)

\(=5.\frac{30}{31}=\frac{150}{31}\)

\(L=\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+\frac{1}{775}+\frac{1}{1147}\)

\(L.6=\frac{6}{1.7}+\frac{6}{7.13}+\frac{6}{13.19}+\frac{6}{19.25}+\frac{6}{25.31}\)

\(L.6=\left(1-\frac{1}{7}\right)+\left(\frac{1}{7}-\frac{1}{13}\right)+\left(\frac{1}{13}-\frac{1}{19}\right)+\left(\frac{1}{19}-\frac{1}{25}\right)+\left(\frac{1}{25}-\frac{1}{31}\right)\)

\(L.6=1-\frac{1}{31}\)

\(L.6=\frac{31}{31}-\frac{1}{31}\)

\(L.6=\frac{25}{31}\)

\(L=\frac{30}{31}:6\)

\(L=\frac{30}{31}.\frac{1}{6}\)

\(L=\frac{30}{186}\)

1 There is a few water in the bottle

=> There is a little water in the bottle

2 The story is between we house and the movie theater

=> The story is between our house and the movie theater

3 Last summer my parents buyed me a lot of different gifts 

=> Last summer my parents bought me a lot of different gifts 

1. few water => little water

2. we house => our house

3. buyed => bought

HỌC TỐT ^_^

để 3n+4/n-1 là số nguyên

=>3n+4 chia hết cho n-1

ta có: 3n+4=3.(n-1)+7 chia hết cho n-1

mà 3.(n-1) chia hết cho n-1

=>7 chia hết cho n-1

=>n-1 thuộc Ư(7)={-7;-1;1;7}

ta có bảng sau:

vậy n thuộc {-6;0;2;8}

để 3n+4/n-1 là số nguyên

=>3n+4 chia hết cho n-1

ta có: 3n+4=3.(n-1)+7 chia hết cho n-1

mà 3.(n-1) chia hết cho n-1

=>7 chia hết cho n-1

=>n-1 thuộc Ư(7)={-7;-1;1;7}

ta có bảng sau:

vậy n thuộc {-6;0;2;8}

\(A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{48.50}\)

\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{48}-\frac{1}{50}\)

\(=1-\frac{1}{50}\)

\(=\frac{50}{50}-\frac{1}{50}\)

\(=\frac{49}{50}\)

Ta có:\(\frac{49}{50}\)và\(\frac{3}{2}\)

Vì\(\frac{49}{50}< 1;\frac{3}{2}>1\)

\(\Rightarrow\frac{49}{50}< \frac{3}{2}\)

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