Tính :
\(D=\frac{a^3+3^3}{b^3+4^3}\text{ biết }\frac{a+b}{a-3}=\frac{b+4}{b-4}\)
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\(P=\dfrac{3x^2+1-3x^2+6x-3}{3x^2+1}=1-\dfrac{3\left(x-1\right)^2}{3x^2+1}\le1\)
\(P_{max}=1\) khi \(x=1\)
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
\(TH1:3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=\frac{1}{3}\)
\(TH2:\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(x=10\)
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
TH1:
\(3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=1\div3\)
\(x=\frac{1}{3}\)
TH2:
\(\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=0-5\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(\Leftrightarrow x=-5.\left(-2\right)\)
\(x=10\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=10\end{cases}}\)
a) \(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}.\)
b) \(\frac{-3}{8}+\frac{7}{4}+\frac{1}{12}=\frac{3}{8}+\frac{1}{12}=\frac{36}{96}+\frac{8}{96}=\frac{48}{96}=\frac{1}{2}\)
c) \(\frac{3}{5}\div\left(\frac{1}{4}\div\frac{7}{5}\right)=\frac{3}{5}\div\frac{5}{28}=\frac{3}{5}.\frac{28}{5}=\frac{84}{25}\)
d) \(\frac{10}{11}+\frac{4}{11}\div4-\frac{-1}{8}=\left(\frac{14}{11}\div4\right)-\frac{-1}{8}=\frac{7}{22}-\frac{1}{8}=\frac{56}{176}-\frac{22}{176}=\frac{34}{176}=\frac{17}{88}\)
e) \(\frac{5}{13}.\frac{8}{15}+\frac{5}{13}.\frac{26}{15}-\frac{5}{13}.\frac{8}{15}=\frac{5}{13}.\left(\frac{8}{15}+\frac{26}{15}-\frac{8}{15}\right)=\frac{5}{13}.\frac{26}{15}=\frac{130}{195}=\frac{26}{39}\)
\(\frac{5}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{7}{6}\)
\(=\left(\frac{5}{6}+\frac{7}{6}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)\)
\(=\frac{12}{6}+\frac{18}{9}+\frac{26}{13}\)
\(=2+2+2\)
\(=4+2\)
\(=6\)
\(\frac{5}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{7}{6}.\)
\(=\left(\frac{5}{6}+\frac{7}{6}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)\)
\(=\frac{12}{6}+\frac{26}{13}+\frac{18}{9}\)
\(=2+2+2\)
\(=6\)
Tổng số lít nước là : \(24\times120=2880\text{ lít}\)
Nếu mỗi thùng chứa được 160 lít nước thì số thùng cần để chứa nước là :
\(2880:160=18\text{ thùng}\)
Sửa đề \(D=\frac{a^3+3^3}{b^3+4^3}\)biết \(\frac{a+3}{a-3}=\frac{b+4}{b-4}\)
\(\Leftrightarrow\left(a+3\right)\left(b-4\right)=\left(a-3\right)\left(b+4\right)\)
\(\Leftrightarrow ab-4a+3b-12=ab+4a-3b-12\)
\(\Leftrightarrow8a=6b\)
\(\Leftrightarrow\frac{a}{6}=\frac{b}{8}\Leftrightarrow\frac{a}{3}=\frac{b}{4}\)
Đặt \(\frac{a}{3}=\frac{b}{4}=k\)\(\Rightarrow a=3k,b=4k\)
\(\Rightarrow D=\frac{a^3+3^3}{b^3+4^3}=\frac{\left(3k\right)^3+3^3}{\left(4k\right)^3+4^3}\)
\(=\frac{3^3\left(k^3+1\right)}{4^3\left(k^3+1\right)}=\frac{3^3}{4^3}=\frac{27}{64}\)
TL:
8 nhé
HNJK