\(A=2^0+2^1+2^2+2^3+...+2^{98}+2^{99}\)

\(\Rightarrow A=\left(2^0+2^1\right)+2^2\left(2^0+2^1\right)+...+2^{98}\left(2^0+2^1\right)\)

\(\Rightarrow A=3+2^2.3+...+2^{98}.3\)

\(\Rightarrow A=3.\left(1+2^2+...+2^{98}\right)⋮3\)

Vậy \(A⋮3\)

Giúp mình với ạ. Mai mình đi học mất tiêu òii

Giúp mình với ạ, mai mình đi học rồi

... sorry tui mới lớp 5

Ta có: \(1,35=\dfrac{27}{20}\)

\(\dfrac{7}{5}=\dfrac{7.4}{5.4}=\dfrac{28}{20}\)

Vì \(28>27\) nên \(\dfrac{28}{20}>\dfrac{27}{20}\)

Vậy \(\dfrac{7}{5}>1,35\)

5⁹.a⁷ : ( 5⁸.a⁶) = (5⁹ : 5⁸) .(a⁷ : a⁶) = 5.a

   13⁵.17³.a⁹.(13.17².a³)

= 13⁵.17³.13.17².a⁹.a³

= (13⁵.13).(17³.17²).(a⁹.a³)

= 13⁶.17⁵.a¹²

\(\Leftrightarrow\left(x+x+x+...+x\right)+\left(1+2+3+4+5+...+50\right)=7500\)

\(\Leftrightarrow50x+50.\left(50+1\right):2=7500\)

\(\Leftrightarrow50x+1275=7500\)

\(\Leftrightarrow50x=6225\)

\(\Leftrightarrow x=124,5\)

Giúp mình với 

a⁴².a³⁴.a = a^42+34+1 = a⁷⁷

\(x^{13}\) : 3⁷ = 3⁶

\(x^{13}\)         = 3⁶ x 3⁷

\(x^{13}\)        = 3¹³

\(x\)          = 3

\(x^{13}:3^7=3^6\)

\(x^{13}=3^6.3^7\)

\(x^{13}=3^{13}\)

\(\Rightarrow x=3\)

\(\left(2^2\right)^8.2^{20}=2^{16}.2^{20}=2^{36};\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4\)\(=3^{24}.3^{15}.3^{16}=3^{55}\)

\(64^3.4^5.16^2=\left(4^3\right)^3.4^5.\left(4^2\right)^2=4^9.4^5.4^4=4^{18}\)