1) \(x^2+\frac{8}{9}=\frac{41}{36}\)\(\Leftrightarrow x^2=\frac{1}{4}\Leftrightarrow x=\pm\frac{1}{2}\)

2) \(\left(x-3\right)^2+-\frac{9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(\Leftrightarrow\left(x-3\right)^2=1\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=1\\x-3=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4\\x=2\end{cases}}\)

3) \(\frac{3}{11}.\frac{22}{6}-\left(x-1\right)^2=\frac{7}{16}\)

\(\Leftrightarrow\left(x-1\right)^2=\frac{9}{16}\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{3}{4}\\x-1=-\frac{3}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{4}\\x=\frac{1}{4}\end{cases}}\)

4) \(1+\left(x+1\right)^3=\frac{37}{64}\)

\(\Leftrightarrow\left(x+1\right)^3=-\frac{27}{64}\)

\(\Rightarrow x+1=-\frac{3}{4}\)

\(\Leftrightarrow x=-\frac{7}{4}\)

5) \(\left(x-\frac{1}{2}\right)^2-\frac{9}{16}=1\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2=\frac{25}{16}\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{5}{4}\\x-\frac{1}{2}=-\frac{5}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{4}\\x=-\frac{3}{4}\end{cases}}\)

6) Bn ghi rõ đề nha mk ko hiểu 

6 ) \(\frac{3-x}{5-x}=\left(\frac{-3}{5}\right)^2\)

\(\frac{3-x}{5-x}=\frac{9}{25}\Leftrightarrow\frac{3-x}{5-x}-\frac{9}{25}\Leftrightarrow\frac{75-25x}{125-25x}-\frac{45-9x}{125-5x}=0\)

\(\Rightarrow\frac{75-25-45+9x}{125-25x}=0\Leftrightarrow5+9x=0\Leftrightarrow x=\frac{-5}{9}\)

1 

\(\left(x-2\right):2.3=6\)

\(\Leftrightarrow\left(x-2\right):2=2\)

\(\Leftrightarrow\left(x-2\right)=4\)

\(\Leftrightarrow x=4+2=6\)

c) ta có

\(\left[\left(2x+1\right)+1\right]m:2=625\)

\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)

\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)

\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)

\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)

\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)

\(\Leftrightarrow\left(2x+1\right)^2=1250\)

...

2

\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)

\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)

\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)

em cháo anh

em giải được đấy 

dạ 534537678657gbjgffgbnsy n58ynvu g3yvt7845y75y4 ko làm mà đòi có ăn

em em đánh xin lỗi

8^x = 1

=> x = 0

Vậy: x = 0

sai r bạn ê

               Bài làm

Sở thích của tôi là:viết về sở thích của tôi.

Ngắn vậy đủ chưa bạn?

Hello everybody!My name is .... I'm ... years old.Today i want to tell you about my hobby.I have many hobbies but i listening to music most.There are many reason to explain why i listening to music.Firstly,i can listen to music after study hard to relax.Secondly,there are many lessons for me to learn from each singer.Thirdly,i can share this hobby with my classmate.Thanks for reading!Good bye and good luck to you!

a) Ta có : 16^x = 2¹⁰⁰

=> (2⁴)^x = 2¹⁰⁰

=> 2^4x = 2¹⁰⁰

=> 4x = 100

=> x = 25

b) 5^x = 125

=> 5^x = 5³

=> x = 3

Bg

a)16^x = 2¹⁰⁰ 

 (2⁴)^x = 2¹⁰⁰ 

  2^4.x = 2¹⁰⁰  (100 =4.25)

  2^4.x = 2^4.25 

      x = 25

b) 5^x = 125

    5^x = 5³ 

    x   = 3

Ta có : S = 1 + 2 + 2² + ... + 2²⁰²⁰

=> 2S = 2 + 2² + 2³ + ... + 2²⁰²¹

Lấy 2S trừ S theo vế ta có : 

2S - S = (2 + 2² + 2³ + ... + 2²⁰²¹) - (1 + 2 + 2² + ... + 2²⁰²⁰)

        S = 2²⁰²¹ - 1

Lại có  5.2²⁰¹⁹ = (2² + 1).2²⁰¹⁹ = 2²⁰²¹ + 2²⁰¹⁹ > 2²⁰²¹ - 1 = S

=> 5.2²⁰¹⁹ > S

Câu 1 . A<B
Câu 2 .A<B