a) 22 . 3 – (110 + 7) : 326
b) 1 + 2 + 3 + … + 2019 + 2010
c) 64 : 4 + 2 . 52
d) 2008 . 213 + 87 . 2008
e) 12 : {390 : [500 – (125 + 35 . 7)]}
g) 33 . 118 – 33 . 18
h) 150 – [102 – (14 – 11) . 2] : 9
i) 4. 52 – 3 .
Mong mọi người giúp mình vs ạ
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\(a,\left(48\cdot0,75-240:10\right)-\left(16\cdot0,5-16:4\right)\)
\(=\left(48\cdot0,75-240\cdot0,1\right)-\left(16:2-16:4\right)\)
\(=\left(36-24\right)-\left(8-4\right)\)
\(=12-4=8\)
\(b,\left(\frac{1}{2}+\frac{3}{5}-\frac{2}{15}\right):\frac{3}{5}\)
\(=\left(\frac{11}{10}-\frac{2}{15}\right):\frac{3}{5}\)
\(=\frac{29}{30}:\frac{3}{5}=\frac{145}{90}=\frac{29}{18}\)
\(c,\left(\frac{13}{84}\cdot\frac{2}{5}-\frac{1}{2}\cdot\frac{7}{180}\right):\frac{27}{18}+\frac{1}{2}\cdot\frac{1}{10}\)
\(=\left(\frac{26}{420}-\frac{7}{360}\right):\frac{3}{2}+\frac{1}{20}\)
\(=\left(\frac{13}{210}-\frac{7}{360}\right):\frac{3}{2}+\frac{1}{20}\)
\(=\frac{107}{2520}:\frac{3}{2}+\frac{1}{20}\)
\(=\frac{214}{7560}+\frac{1}{20}=\frac{214}{7560}+\frac{378}{7560}\)
\(=\frac{592}{7560}=\frac{74}{945}\)
Trả lời:
a, \(\left(48\times0,75-240\div10\right)-\left(16\times0,5-16\div4\right)\)
\(=\left(36-24\right)-\left(8-4\right)\)
\(=12-4\)
\(=8\)
b,\(\left(\frac{1}{2}+\frac{3}{5}-\frac{2}{15}\right)\div\frac{3}{5}\)
\(=\left(\frac{11}{10}-\frac{2}{15}\right)\times\frac{5}{3}\)
\(=\frac{29}{30}\times\frac{5}{3}\)
\(=\frac{29}{18}\)
c,\(\left(\frac{13}{84}\times\frac{2}{5}-\frac{1}{2}\times\frac{7}{180}\right)\div\frac{27}{18}+\frac{1}{2}\times\frac{1}{10}\)
\(=\left(\frac{13}{210}-\frac{7}{360}\right)\times\frac{18}{27}+\frac{1}{2}\times\frac{1}{10}\)
\(=\frac{107}{2520}\times\frac{18}{27}+\frac{1}{20}\)
\(=\frac{107}{3780}+\frac{1}{20}\)
\(=\frac{74}{945}\)
\(\left(a\right)2,52:0,56\cdot7,2:2,5\)
\(=4,5\cdot7,2:2,5\)
\(=32,4:2,5=12,96\)
\(\left(b\right)4,36+13,734:13,08-2,716\)
\(=4,36+1,05-2,716\)
\(=5,41-2,716=2,694\)
\(\left(c\right)\frac{5}{13}\cdot\left(\frac{5}{20}-\frac{1}{10}\right)+\frac{2}{5}\)
\(=\frac{5}{13}\cdot\left(\frac{5}{20}-\frac{2}{20}\right)+\frac{2}{5}\)
\(=\frac{5}{13}\cdot\frac{3}{20}+\frac{2}{5}\)
\(=\frac{15}{260}+\frac{2}{5}=\frac{15}{260}+\frac{104}{260}\)
\(=\frac{119}{260}\)
Trả lời:
a, \(2,52\div0,56\times7,2\div2,5\)
\(=4,5\times7,2\div2,5\)
\(=32,4\div2,5\)
\(=12,96\)
b,\(4,36+13,734\div13,08-2,716\)
\(=4,36+1,05-2,716\)
\(=5,41-2,716\)
\(=2,694\)
c,\(\frac{5}{13}\times\left(\frac{5}{20}-\frac{1}{10}\right)+\frac{2}{5}\)
\(=\frac{5}{13}\times\frac{3}{20}+\frac{2}{5}\)
\(=\frac{3}{52}+\frac{2}{5}\)
\(=\frac{119}{260}\)
Viet Nam is in the Soul - East Asia . It has lots of beautiful mountains rivers and beaches . There are tow long river the mekong rivers is the south rive in the soul east asia and of couse it is longer than the red rivers . The mekong river starts in tibet and flows into to the bien dong phanxipang is the hingest mountian in Viet Nam . It 3,14 meters Viet Nam aslo has many nice beaches such as Sam Son , Nha Trang , Vung tau .
Học tốt
1. lots
2. there
3. river
4. south
5. longest
6. than
7. flows into
8. the
9. heigh
10. has
j) \(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}=\left(\frac{8}{3}.\frac{3}{8}\right).\left(\frac{2}{5}.10\right).\frac{19}{92}=1.4.\frac{19}{92}\)
\(=\frac{19}{23}\)
k)\(\frac{-5}{7}.\frac{2}{11}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}=\left(\frac{2}{11}.\frac{19}{12}\right).\left(\frac{-13}{17}.\frac{17}{13}\right).\frac{-5}{7}\)
\(=\frac{-19}{66}.\frac{-5}{7}=\frac{95}{462}\)
l)\(\frac{12}{19}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}=\left(\frac{12}{19}.\frac{19}{12}\right).\left(\frac{-13}{17}.\frac{17}{13}\right).\frac{7}{15}\)
\(=\frac{-7}{15}\)
cậu tham khảo trên này ạ, nếu đúng cho mk 1 t.i.c.k ạ, thank nhiều
e. \(\frac{-3}{5}\cdot\frac{5}{7}+\frac{-3}{5}\cdot\frac{3}{7}+\frac{-3}{5}\cdot\frac{6}{7}=-\frac{3}{5}\left(\frac{5}{7}+\frac{3}{7}+\frac{6}{7}\right)=-\frac{3}{5}\cdot2=-\frac{6}{5}\)
f. \(\frac{1}{3}\cdot\frac{4}{5}+\frac{1}{3}\cdot\frac{6}{5}-\frac{4}{5}=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}\right)-\frac{4}{5}=\frac{1}{3}\cdot2-\frac{4}{5}=\frac{2}{3}-\frac{4}{5}=-\frac{2}{15}\)
g. \(\frac{4}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{15}{19}+\frac{5}{7}=-\frac{3}{7}\left(\frac{4}{19}+\frac{15}{19}\right)+\frac{5}{7}=-\frac{3}{7}\cdot1+\frac{5}{7}=-\frac{3}{7}+\frac{5}{7}=\frac{2}{7}\)
h. \(\frac{5}{9}\cdot\frac{7}{13}+\frac{5}{9}\cdot\frac{9}{13}-\frac{5}{9}\cdot\frac{3}{13}=\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)=\frac{5}{9}\cdot1=\frac{5}{9}\)
a) \(2x^2-72=0\)
\(\Leftrightarrow2\left(x^2-36\right)=0\Leftrightarrow x^2-36=0\Leftrightarrow x=_-+6\)
\(2x^2-72=0\)
\(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x=\sqrt{36}=6\)
b) số xấu
\(\left[\frac{3}{4}-x\right]^3=-8\)
\(\Leftrightarrow\left[\frac{3}{4}-x\right]^3=\left(-2\right)^3\)
\(\Leftrightarrow\frac{3}{4}-x=-2\)
\(\Leftrightarrow x=\frac{3}{4}-\left(-2\right)\)
\(\Leftrightarrow x=\frac{3}{4}+2=\frac{3}{4}+\frac{8}{4}=\frac{11}{4}\)
\(\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{\left(7255+1\right)\cdot4375-725}{3650+4375\cdot7255}\)
\(=\frac{7255\cdot4375+4375-725}{3650+4375\cdot7255}=\frac{7255\cdot4375+3650}{3650+4375\cdot7255}\)
\(\frac{7255\cdot4375+3650}{7255\cdot4375+3650}=1\)
=(7255+1)x4375-725 / 3650+4375x7255
=4375x7255+4375-725 / 3650+4375x7255
=4375x7255+3650 / 4375x7255+3650
=1
\(a)22.3-\left(110+7\right):326\)
\(=66-117:326\)
\(=66-\frac{117}{326}\)
\(=\frac{21399}{326}\)
\(b)1+2+3+.....+2019+2010\)
Ta tạm để số 2010 ra ngoài .
Số số hạng của tổng trên là :
( 2019 - 1 ) : 1 + 1 = 2019 ( sh )
Tổng trên là :
\(\left(2019+1\right)\times2019:2=2039190\)
\(\Rightarrow2039190+2010=2041200\)
\(c)64:4+2.52\)
\(=16+104\)
\(=120\)
\(d)2008.213+87.2008\)
\(=2008.\left(213+87\right)\)
\(=2008.300\)
\(=602400\)
\(e)12: \left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3=4\)
\(g)33.118-33.18\)
\(=3894-594\)
\(=3300\)
\(h)150-\left[102-\left(14-11\right).2\right]:9\)
\(=150-\left[102-6\right]:9\)
\(=150-96:9\)
\(=150-\frac{32}{33}\)
\(=\frac{4918}{33}\)
\(i)4.52-3\)
\(=208-3\)
\(=205\)