Cho 6 số nguyên dương a, b, c, d, m, n thỏa a<b<c<d<m<n
Chứng minh rằng \(\frac{a+c+m}{a+b+c+d+m+n}\)<\(\frac{1}{2}\)
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câu 1 mk ko biết
2) => If you are a vegetariane, you won"t eat meat.
If you are a teacher, you will work hard.
One of my hobbies is listening to music, especially English songs. My hobby started when I was a first – year student at Da Nang University of Technology. I spend much time on it. I can listening when I am doing my housework such as clean the floor, wash clothes, wash dish…or when I sleep…I love Taylor Swift, Rihana…they are great singers. I can learn English vocabulary when listening to English songs and it also make me feel relaxed.
I think it a good hobby and I will never stop it.
Watching television is my favourite activities I use to do in my free time. I love watching sports programs on Saturday mornings and cartoons on Sunday afternoons. I usually watch movie during all days of week after I have completed my homework at school. At night, I especially enjoy watching situation comedies and movies. If I have a huge number of school work, I try to manage my schedule so that I will able to see at least 1 of my favorite TV shows. Watching TV isn’t the only indoor activity that I can do in my free time. I also have some other favorite activities such as going shopping with my mother or friends and making paper flowers. However, when I have free time, I spend a lot of time on watching TV than other activities. Watching TV can support me not only relax but also build my knowledge about the open world.
K nhé?
1) ( 5 - 3x ) ( 1 + x ) = 0
=> \(\orbr{\begin{cases}5-3x=0\\1+x=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}\)
Vậy x = - 1 hoặc x = \(\frac{5}{3}\)
2) x2 - 3x = 0
=> x ( x - 3 ) = 0
=> \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy x = 0 hoặc x = 3
3) 4x + 2x2 = 0
=> 2x ( x + 2 ) = 0
=> \(\orbr{\begin{cases}2x=0\\x+2=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)
Vậy x = 0 hoặc x = - 2
\(a,\left(5-3x\right)\left(1+x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}5-3x=0\\1+x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}3x=5\\x=-1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}}\)
vậy_
\(b,x^2-3x=0\)
\(\Leftrightarrow x\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}}\)
vậy_
\(c,4x+2x^2=0\)
\(\Leftrightarrow x\left(4+2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\4+2x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\2x=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=-2\end{cases}}}\)
vậy_
a, Số hs giỏi là:
40 . 1/8 = 5 (hs)
Số hs còn lại là:
40 - 5 = 35 (hs)
Số hs khá là:
35 . 2/5 = 14 (hs)
Số hs yếu là:
14 . 3/7 = 6 (hs)
Đ/S: giỏi: 5 hs
khá: 14 hs
trung bình: 6 hs
A) x-1=0 x+2=0
x=1 x=-2
vậy x =1 hoặc x=-2
B) 2x-1=0 3x+2=0
2x=1 3x=2
x=\(\frac{1}{2}\) x=\(\frac{2}{3}\)
vậy x=1/2 hoặc x=2/3
c) 2x=0 x-1/2 =0
x=0 x=1/2
vậy x=0 hoặc x=1/2
a) ( x - 1 ) ( x + 2 ) = 0
=> \(\orbr{\begin{cases}x-1=0\\x+2=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=1\\x=-2\end{cases}}\)
Vậy x = 1 hoặc x = - 2
b) ( 2x - 1 ) ( 3x + 2 ) = 0
=> \(\orbr{\begin{cases}2x-1=0\\3x+2=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=1\\3x=-2\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{-2}{3}\end{cases}}\)
Vậy x = \(\frac{1}{2}\)hoặc x = \(\frac{-2}{3}\)
c) \(2x\left(x-\frac{1}{2}\right)=0\)
=> \(\orbr{\begin{cases}2x=0\\x-\frac{1}{2}=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=\frac{1}{2}\end{cases}}\)
Vậy x = 0 hoặc x = \(\frac{1}{2}\)
Vì \(\left|x+4\right|\ge0;\left|y-3\right|\ge0\)
mà |x+4| + |y-3| =3 và |x+4| ; |y-3| thuộc Z
\(\Rightarrow\left(\left|x+4\right|;\left|y-3\right|\right)\in\left\{\left(0;3\right)\left(1;2\right)\left(3;0\right)\left(2;1\right)\right\}\)
Tương ứng \(\left(x;y\right)\in\left\{\left(-4;6\right);\left(-3;5\right);\left(-1;3\right);\left(-2;4\right)\right\}\)
Vậy \(\left(x;y\right)\in\left\{\left(-4;6\right);\left(-3;5\right);\left(-1;3\right);\left(-2;4\right)\right\}\)
-1/5 . (9/8 + 16/32 - 12/46) - 9/17
= -1/5 . (9/8 + 1/2 - 6/23) - 9/17
= -1/5 . (9/8 + 4/8 - 6/23) - 9/17
= -1/5 . (13/8 - 6/23) - 9/17
= -1/5 . 251/184 - 9/17
= -251/920 - 9/17
= -4267/15640 - 8280/15640
= -12547/15640
ai làm đk mình k cho
Ta có: a < b => 2a < a + b
c < d => 2c < c + d
m < n => 2m < m +n
suy ra: 2 ( a + c + m) < a + b + c + d + m + n
=> \(\frac{a+c+m}{a+b+c+d+m+n}< \frac{1}{2}\)