50 /75 = x- 12 /81
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(55 + 65 + 75 + 85 + 95) : y =5
475 : y = 5
y = 475 : 5
y = 95
Học tốt
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\(\left(x-273\right)\left(1+3+5+...+2005\right)=0\)
Vì \(\left(1+3+5+...+2005\right)\ne0\Rightarrow x-273=0\)
\(\Leftrightarrow x=273\)
(x-273) . (1+3+5+...+2005)=0
=>(x-273) =0
x = 273
Học tốt
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\(\frac{1}{2}\)\(+\)\(\frac{1}{6}\)\(+\)\(\frac{1}{12}\)\(+\)\(\frac{1}{20}\)\(+\)\(\frac{1}{30}\)\(+\)\(\frac{1}{x}\)\(=\)\(\frac{41}{42}\)
\(\frac{1}{1.2}\)\(+\)\(\frac{1}{2.3}\)\(+\)\(\frac{1}{3.4}\)\(+\)\(\frac{1}{4.5}\)\(+\)\(\frac{1}{5.6}\)\(+\)\(\frac{1}{x}\)\(=\)\(\frac{41}{42}\)
\(\frac{1}{1}\)\(-\)\(\frac{1}{6}\)\(+\)\(\frac{1}{x}\)\(=\)\(\frac{41}{42}\)
\(\frac{5}{6}\)\(+\)\(\frac{1}{x}\)\(=\)\(\frac{41}{42}\)
\(\frac{1}{x}\)\(=\)\(\frac{1}{7}\)
\(x=7\)
- ╰☆☆нєν✰.✰νũ❤‿✶(*•.¸♡ţęąɱ ƒŗęę ƒįŗę❤☆) sai rồi nhé
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{x}=\frac{41}{42}\)
\(\Leftrightarrow\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{x}=\frac{41}{42}\)
\(\Leftrightarrow\frac{5}{6}+\frac{1}{x}=\frac{41}{42}\Leftrightarrow\frac{1}{x}=\frac{41}{42}-\frac{5}{6}=\frac{1}{42}\Leftrightarrow x=42\)
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\(\frac{9}{14}-\frac{x}{7}:\frac{5}{3}=\frac{3}{14}\)
\(\frac{9}{14}-\frac{x}{7}=\frac{3}{14}.\frac{5}{3}\)
\(\frac{9}{14}-\frac{x}{7}=\frac{5}{14}\)
\(\frac{x}{7}=\frac{9}{14}-\frac{5}{14}\)
\(\frac{x}{7}=\frac{2}{7}\)
\(\Rightarrow x=2\)
\(\frac{9}{14}\)\(-\)\(\frac{x}{7}\)\(:\)\(\frac{5}{3}\)\(=\frac{3}{14}\)
\(\frac{9}{14}\)\(-\)\(\frac{3x}{35}\)\(=\frac{3}{14}\)
\(\frac{3x}{35}\)\(=\)\(\frac{3}{7}\)
\(3x=15\)
\(x=5\)
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Sau lần lấy đầu tiên, trong thùng còn số ki-lô-gam đường là:
28,75 – 10,5 = 18,25 ( kg )
Sau hai lần lấy, trong thùng còn số ki-lô-gam đường là:
18,25 – 8 = 10,25 ( kg )
Đáp số : 10,25 kg .
#Ry
x - 12/81 = 50/75
x = 50/75 + 12/81
x = 22/27
x -12/81 = 50/75
x = 50/75 + 12 /81
x 22/27