Ta có: 12⁴⁵=12^3.15=1728¹⁵

Vì 625¹⁵<1728¹⁵ nên 625¹⁵<12⁴⁵

Ta có: 12⁴⁵=12^3.15=1728¹⁵

Vì 625¹⁵<1728¹⁵ nên 625¹⁵<12⁴⁵

a)\(\frac{a}{b}< \frac{c}{d}\Rightarrow\frac{a}{b}.bd< \frac{c}{d}.bd\Rightarrow ad< cb\)(đpcm)

b)Ta có: 

• ad<cd

=>ab+ad<ab+cd

=>a(b+d)<b(b+d)

=>\(\frac{a\left(b+d\right)}{b\left(b+d\right)}< \frac{b\left(a+c\right)}{b\left(b+d\right)}\)

=>\(\frac{a}{b}< \frac{a+c}{b+d}\)(1)

•  ad<bc

=>ad+cd<bc+cd

=>d(a+c)<c(b+d)

=>\(\frac{d\left(a+c\right)}{d\left(b+d\right)}< \frac{c\left(b+d\right)}{d\left(b+d\right)}\)

=>\(\frac{a+c}{b+d}< \frac{c}{d}\)(2)

Từ (1) và (2) => \(\frac{a}{b}< \frac{a+c}{b+d}< \frac{c}{d}\)(đpcm)

a)(-7 / 5 + 3 / 8 ) : 2009 / 2010 + (-3 / 5+5 / 8) : 2009 / 2010

=[ (-7 / 5 + 3 / 8 ) + (-3 / 5+5 / 8) ] : 2009/2010

=[ -7/5 +3/8 + (-3)/5+5/8 ] : 2009/2010

=[ (-7/5 + (-3)/5) + (3/8 + 5/8) ] :2009/2010

=[-2+1] : 2009/2010

=-1 :2009/2010

=-2009/2010

b)\(\frac{9^8\cdot4^3}{27^4\cdot6^5}=\frac{\left(3^2\right)^8\cdot\left(2^2\right)^3}{\left(3^3\right)^4\cdot\left(2\cdot3\right)^5}=\frac{3^{16}\cdot2^6}{3^{12}\cdot2^5\cdot3^5}=\frac{3^{16}\cdot2^5\cdot2}{3^{16}\cdot3^1\cdot2^5}=\frac{2}{3^1}=\frac{2}{3}\)

123654321

123654321

cach giai

goi a la so can tim ta co

a chia het cho 2,3,4,5,6 suy ra cstc la 0

tiep theo a chia het cho 7,8,9 suy ra 

mk hết bít xin lỗi bn

\(15\frac{3}{40}.\frac{594}{40}-\frac{3}{40}.\left(-14\right)+\frac{3}{40}.\frac{23}{20}\)

\(=201.\frac{3}{40}.\frac{594}{40}-\frac{3}{40}.\left(-14\right)+\frac{3}{40}.\frac{23}{20}\)

\(=\frac{3}{40}.\frac{11859}{40}-\frac{3}{40}.\left(-14\right)+\frac{3}{40}.\frac{23}{20}\)

\(=\frac{3}{40}.\left(\frac{11859}{40}-\left(-14\right)+\frac{23}{20}\right)\)

\(=\frac{3}{40}.\frac{2493}{8}\)

\(=\frac{7579}{320}\)

7579/320

goi so tien la a nghin dong ;

gia tien 1kg bot mi truoc day :a: 32,9[nghin dong]

...

Ta có : 32,9 : 40 = 82.25 %

=> Bột mỳ dc hạ giá 17,75 % ( so vs ban đầu )

ok Tích cho mk nhé