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Trong câu văn trên, trạng ngữ "Theo nghiên cứu của Quỹ Nhi đồng Liên Hợp Quốc (UNICEF)" có chức năng làm rõ nguồn gốc hoặc cơ sở của thông tin được trình bày. Nó cung cấp thông tin về nguồn của nghiên cứu và nguồn tin cậy đằng sau số liệu được nêu ra trong câu. Đồng thời, nó giúp tăng tính minh bạch và uy tín cho thông tin được đưa ra.
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1) a little
2) a few
3) little
4) few
5) a little
6) a few
7) little
8) few
9) little
10) a few
11) a little
12) Few
13) a few
14) few
15) little
16) little
17) few
18) little
19) a few
20) a little
1) I have ____a little___ water left. There's enough to share.
2) I have ___a few_____ good friends. I'm not lonely.
3) He has _____little____ education. He can't read or write, and he can hardly count.
4) There are _____few____ people she really trusts. It's a bit sad.
5) We've got _____a little____ time at the weekend. Would you like to meet?
6) Julie gave us _____a few___ apples from her garden. Shall we share them?
7) She has ___little_____ self-confidence. She has a lot of trouble talking to new people.
8) There are ____few______ women politicians in the UK. Many people think there should be more.
9) It's a great pity, but the hospital has _______little__ medicine. They can't help many people.
10) I've got ___a few_____ cakes to give away. Would you like one?
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xy+2y-8=4x+35
=>xy+2y-4x=43
=>y(x+2)-4x-8=35
=>(x+2)(y-4)=35
=>\(\left(x+2\right)\left(y-4\right)=1\cdot35=35\cdot1=\left(-1\right)\cdot\left(-35\right)=\left(-35\right)\cdot\left(-1\right)=5\cdot7=7\cdot5=\left(-5\right)\cdot\left(-7\right)=\left(-7\right)\cdot\left(-5\right)\)
=>\(\left(x+2;y-4\right)\in\left\{\left(1;35\right);\left(35;1\right);\left(-1;-35\right);\left(-35;-1\right);\left(5;7\right);\left(7;5\right);\left(-5;-7\right);\left(-7;-5\right)\right\}\)
=>\(\left(x;y\right)\in\left\{\left(-1;39\right);\left(33;5\right);\left(-3;-31\right);\left(-37;3\right);\left(3;11\right);\left(5;9\right);\left(-7;-3\right);\left(-9;-1\right)\right\}\)
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\(10A=\dfrac{10^{2022}+10}{10^{2022}+1}=1+\dfrac{9}{10^{2022}+1}\)
\(10B=\dfrac{10^{2023}+10}{10^{2023}+1}=1+\dfrac{9}{10^{2023}+1}\)
Ta có: \(10^{2022}+1< 10^{2023}+1\)
=>\(\dfrac{9}{10^{2022}+1}>\dfrac{9}{10^{2023}+1}\)
=>\(1+\dfrac{9}{10^{2022}+1}>1+\dfrac{9}{10^{2023}+1}\)
=>10A>10B
=>A>B
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ĐKXĐ: n<>-1/2
Để B là số nguyên thì \(6n-8⋮2n+1\)
=>\(6n+3-11⋮2n+1\)
=>\(-11⋮2n+1\)
=>\(2n+1\in\left\{1;-1;11;-11\right\}\)
=>\(n\in\left\{0;-1;5;-6\right\}\)
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1. Mandy/not watch/drama/TV/last night/because/she/tired.
→_____Mandy didn't watch TV last night because she was tired ________________________________________
2. be/football match/Friday/exciting/?
→_______Was the football match on Friday exciting?______________________________________
3. Why/not/we/meet/movie theater/6 o'clock
→____Why don't we meet at the movie theater at 6 o'clock?_________________________________________
4. cinema/Miller Street,/opposite/arcade
→___The cinema is on Miller Street, opposite the arcade___________________________________________
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ĐKXĐ: n<>7
Để A là số nguyên thì \(4n+1⋮n-7\)
=>\(4n-28+29⋮n-7\)
=>\(29⋮n-7\)
=>\(n-7\in\left\{1;-1;29;-29\right\}\)
=>\(n\in\left\{8;6;36;-22\right\}\)
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Ta có: \(\text{Trọng lượng = Khối lượng x 10}\)
và \(\text{Khối lượng = Trọng lượng : 10}\)
Cách tính trọng lượng khi biết khối lượng
P=10m�=10�
Cách tính khối lượng khi biết trọng lượng
P=10m⇒m= P/10
Câu 9:
Trên hình vẽ có 6 góc: \(\widehat{AOB};\widehat{AOC};\widehat{AOD};\widehat{BOC};\widehat{BOD};\widehat{COD}\)
Câu 11: