Tim so nguyen x biet
a, 4x=84 d, 16x=328
b, 4x=3224 e, 32x=1610
c, 8x=1612
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\(\frac{1}{2014}-\frac{1}{2014.2013}-\frac{1}{2013.2012}-...-\frac{1}{3.2}-\frac{1}{2.1}.\)
\(=-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2012.2013}+\frac{1}{2013.2014}\right)+\frac{1}{2014}\)
\(=\frac{1}{2014}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2013}-\frac{1}{2014}\right)\)
\(=\frac{1}{2014}-1+\frac{1}{2014}=\frac{1}{1007}-1=\frac{-1006}{1007}\)
....
b)\(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}=\frac{\left(2.0,4\right)^5}{\left(0,4\right)^6}=\frac{2^5.\left(0,4\right)^5}{\left(0,4\right)^6}=\frac{2^5}{0,4}=\frac{2^5}{\frac{2}{5}}=\frac{2^4}{5}=\frac{16}{5}\)
c)\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.3^{12}}{3^6.2^6.2^9}=3^6\)
a)\(\frac{45^{10}.5^{20}}{75^{15}}=\frac{15^{10}.3^{10}.5^{20}}{5^{15}.15^{15}}=\frac{3^{10}.5^5}{15^5}=\frac{3^{10}.5^5}{5^5.3^5}=3^5\)
A = 2100 - 299 + 298 - 297 +...+ 22 - 2
=> 2A = 2101 - 2100+299 - 298+...+23-22
=> 2A+A= 2101 -2
=> \(A=\frac{2^{101}-2}{3}\)
phần B bn lm tương tự nha!
\(a,4^x=8^4\)
\(\Rightarrow2^{2x}=2^{12}\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=12:2\)
\(\Rightarrow x=6\)