bài làm 

Last summer, I went to Nha Trang beach with my family , it was such a memorable summer holiday. We went there by car , and when we nearly got there, from the far distance , I could see how wide and beautiful the beach was. The weather was so nice that made me want to run directly to the beach, enjoy the fresh air and clean water. There were a lot of people swimming , sunbathing, playing volleyball on the shore , and some children even built sand castles and flew kites .We stayed at Edele hotel whose service I found very satisfied and I had the chance to eat the sea food there , they were very delicious . I went to Vinpearl Land , Long Sơn pagoda,too .They were very wonderful. I felt very fun and happy because I also met many foreigners ,they were tourists and I had talked to them a lot . We stayed in Nha Trang for a week and the last day , I went to some gift shop near the beach to buy souvenir for my grandparents and my friends . When I came back home , I felt very happy but a little regretted because I wanted to stay there longer. I told my dad I d Nha Trang and I hoped we can go to Nha Trang again one summer .

giúp em dịch luôn ạ

\(\left(a+b+c\right)^2=3\left(a^2+b^2+c^2\right)_{ }\)

\(a^2+b^2+c^2+2ab+2bc+2ca=3a^2+3b^2+3c^2\)

\(2a^2+2b^2+2c^2-2ab-2bc-2ca=0\)

\(\left(a^2-2ab+b^2\right)+\left(b^2-2bc+c^2\right)+\left(c^2-2ca+a^2\right)=0\)

\(\left(a-b\right)^2+\left(b-c\right)^2+\left(c-a\right)^2=0\)

\(\hept{\begin{cases}a-b=0\\b-c=0\\c-a=0\end{cases}}\)

Do đó  \(P=a^2+\left(a+2\right)\left(2a\right)+2020\)

\(P=a^2+2a^2+4a+2020\)

\(P=3a^2+4a+2020\)

\(3P=9a^2+12a+6060\)

\(3P=\left(3a\right)^2+2.\left(3a\right).2+4+6060-4\)

\(3P=\left(3a+2\right)^2+6056\ge6056\Leftrightarrow3P\ge6056\Leftrightarrow P\ge\frac{6056}{3}\)    Dấu "=" xảy ra khi a = b = c = \(-\frac{3}{2}\)

Vậy P đạt giá trị nhỏ nhất là 6056/3 khi a = b = c = -3/2

1. rained

2. got

3. Did he buy

4. didin't eat

5. worked

6. Did Loan drink

Học tốttttttttttttttttttttttttttt

1 it (rain) a lot in my hometown last month.                   ...........rained.......................

2 i (get) up very late last sunday morning .                    .............got.....................

3 he (buy) a new computer last week?                          ............Did he buy ..................

4 they (not eat) their breakfast this morning.                 ................didn't eat..................

5 we (work) in the factory 5 years ago.                          ..............worked....................

6 Loan (drink) milk in the canteen yesterday?               .................Did Loan drink.................

* Ở bài này , bạn áp dụng cấu trúc thì quá khứ đơn . 

Bài làm:

Ta có: \(\frac{9}{4x^2}+\frac{9y^2}{4}-\frac{9y}{2x}\)

\(=\left(\frac{3}{2x}\right)^2-2.\frac{3}{2x}.\frac{3y}{2}+\left(\frac{3y}{2}\right)^2\)

\(=\left(\frac{3}{2x}-\frac{3y}{2}\right)^2\)

dạ mk cảm ơn bạn De Bruyne nha!

\(\frac{16}{27}\) bé hơn \(\frac{27}{29}\)

Ta có:16:27=0,59;27:29=0,93 nên 16/27<27/29

Bài làm:

Ta có: \(2\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\left(3^4-1\right)\left(3^4+1\right)\)

\(=3^8-1\)

\(=6561-1=6560\)

a) \(\left|x+2\right|>7\)

\(\Leftrightarrow\orbr{\begin{cases}x+2>7\\x+2< -7\end{cases}}\Leftrightarrow\orbr{\begin{cases}x>5\\x< -9\end{cases}}\Leftrightarrow5< x< -9\left(ktm\right)\)

\(\Leftrightarrow\orbr{\begin{cases}x+2< 7\\x+2>-7\end{cases}}\Leftrightarrow\orbr{\begin{cases}x< 5\\x>-9\end{cases}}\Leftrightarrow-9< x< 5\left(tm\right)\)

vậy....

v) \(\left|x-1\right|< 3\)

\(\Leftrightarrow\orbr{\begin{cases}x-1< 3\\x-1>-3\end{cases}}\Leftrightarrow\orbr{\begin{cases}x< 4\\x>-2\end{cases}}\Leftrightarrow-2< x< 4\)

vậy...

a, | x+ 2| > 7

=> x + 2 > 7 hoặc x + 2 > -7

    x > 5                 x > -9 

vậy để | x + 2| > 7 thì x > 5 và x > -9

b, | x -1 |< 3

=> x - 1 < 3  hoặc x - 1< -3

     x < 4               x < -2

vậy để |x - 1| < 3 thì x < 4 và x < -2

câu đầu là 8 người vì sẽ có 8 ông trong đó có ông bị ốm

câu thứ 2 là mà chết sẵn rồi nên nó ko bị làm sao ,còn nếu bị thật thì đi cách li 14 ngày

Câu hỏi 2: Chỉ toàn ông chứ ko có người

Câu hỏi 3: Con ma không tồn tại =>Câu hỏi không tồn tại

1 + 2 + 3 + 4 + ... + 100

= (1 + 100) x 100 : 2

=5050

học tốt!

                              Bài làm :

Tổng trên có giá trị là :

\(\frac{\left(100+1\right)\times100}{2}=5050.\)

                                       Đáp số : 5050

Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!