\(M=\frac{3x+3\sqrt{x}-3}{x+\sqrt{x}-2}-\frac{\sqrt{x}+1}{\sqrt{x}+2}+\frac{\sqrt{x}-2}{\sqrt{x}}.\left(\frac{1}{1-\sqrt{x}}-1\right)\)

\(M=\frac{3x+3\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}-\frac{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)  \(+\frac{\sqrt{x}-2}{\sqrt{x}}.\frac{\sqrt{x}}{\sqrt{x}-1}\)

\(M=\frac{3x+3\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}-\frac{x-1}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\) \(+\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}\)

\(M=\frac{3x+3\sqrt{x}-3-x+1+x-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)

\(M=\frac{3x+3\sqrt{x}-6}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)

\(M=\frac{3\left(x+\sqrt{x}-2\right)}{x+\sqrt{x}-2}\)

\(M=3\)

b) \(\sqrt{x}=M\)

\(\Leftrightarrow x=M^2\)

thay vào ta có: 

\(x=3^2\)

\(x=9\)

c) \(M=3\in N\)

\(\Rightarrow x=3\)

d) \(M>1\Leftrightarrow x>1\)

Người lạ xin kết bạn !

Kb vs e nha a , e hok lop 7!😊

hệ pt <=> x = m-y

                2x-my = 0

<=> x=m-y

       2m-2y-my = 0

<=> x=m-y

       2m = my+2y = y.(m+2)

+, Nếu y = 0 => x = 0

+, Nếu y khác 0 thì :

hệ pt <=> x=m-y

                y = 2m/m+2

<=> x=m - 2m/m+2

       y=2m/m+2

<=> x=m^2/m+2

       y=2m/m+2

Vậy .............

Tk mk nha

\(\sqrt{\left(2x-1\right)^2}=3\)

\(\left|2x-1\right|=3\)

\(\Rightarrow\orbr{\begin{cases}2x-1=3\\2x-1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}2x=4\\2x=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)

vậy....

Ta có :

\(\sqrt{\left(2x-1\right)^2}=3\)

\(\Leftrightarrow\)\(\left(2x-1\right)^2=3^2\)

\(\Leftrightarrow\)\(2x-1=\sqrt{9}\)

\(\Leftrightarrow\)\(2x=3+1\)

\(\Leftrightarrow\)\(x=4:2\)

\(\Leftrightarrow\)\(x=2\)

Vậy \(x=2\)