Tìm tie số phần trăm của 12 và 50
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Câu 1:
a: \(\dfrac{13}{7}\cdot\dfrac{11}{9}-\dfrac{13}{7}\cdot\dfrac{5}{9}-\dfrac{6}{9}\cdot\dfrac{4}{7}\)
\(=\dfrac{13}{7}\left(\dfrac{11}{9}-\dfrac{5}{9}\right)-\dfrac{6}{9}\cdot\dfrac{4}{7}\)
\(=\dfrac{6}{9}\left(\dfrac{13}{7}-\dfrac{4}{7}\right)=\dfrac{6}{9}\cdot\dfrac{9}{7}=\dfrac{6}{7}\)
b: Sửa đề: \(14:\left(4\dfrac{1}{2}-2\dfrac{5}{8}\right)+14\dfrac{1}{2}+\dfrac{2}{3}\)
\(=14:\left(\dfrac{9}{2}-\dfrac{21}{8}\right)+\dfrac{29}{2}+\dfrac{2}{3}\)
\(=14:\dfrac{15}{8}+\dfrac{87+4}{6}\)
\(=\dfrac{112}{15}+\dfrac{91}{6}=\dfrac{679}{30}\)
Câu 2:
a: \(\left(3\dfrac{1}{2}+2x\right)\cdot1\dfrac{1}{3}=2\dfrac{4}{5}\)
=>\(\left(2x+\dfrac{7}{2}\right)\cdot\dfrac{4}{3}=\dfrac{14}{5}\)
=>\(2x+\dfrac{7}{2}=\dfrac{14}{5}:\dfrac{7}{3}=\dfrac{14}{5}\cdot\dfrac{3}{7}=\dfrac{6}{5}\)
=>\(2x=\dfrac{6}{5}-\dfrac{7}{2}=\dfrac{12-35}{10}=\dfrac{-23}{10}\)
=>\(x=-\dfrac{23}{10}:2=-\dfrac{23}{20}\)
b: \(1\dfrac{1}{2}x+75\%=1\)
=>\(1,5x=1-0,75=0,25\)
=>x=0,25:1,5=1/6
Câu 1:
a, 13/7 . 11/9 - 13/7 . 5/9 b,14 : (\(4\dfrac{1}{2}\) - \(2\dfrac{5}{8}\))
= 13/7 . (11/9 - 5/9) = 14 : (9/2 - 21/8)
= 13/7 . 2/3 = 14 : (36/8 - 21/8)
= 26/21 = 14 : 5/8
= 14 . 8/5
= 112/5
Câu 2 : Tìm x , biết
a, (\(3\dfrac{1}{2}+2x\)) .\(1\dfrac{1}{3}\) = \(2\dfrac{4}{5}\)
(\(\dfrac{7}{2}+2x\)) .\(\dfrac{4}{3}\) = \(\dfrac{14}{5}\)
(\(\dfrac{7}{2}+2x\)) = \(\dfrac{14}{5}:\dfrac{4}{3}\)
(\(\dfrac{7}{2}+2x\)) = \(\dfrac{14}{5}\) . \(\dfrac{3}{4}\)
(\(\dfrac{7}{2}+2x\)) = \(\dfrac{7}{5}.\dfrac{3}{2}\)
(\(\dfrac{7}{2}+2x\)) = \(\dfrac{21}{10}\)
\(\dfrac{7}{2}+2x\) = \(\dfrac{21}{10}\)
\(2x\) = \(\dfrac{21}{10}-\dfrac{7}{2}\)
\(2x\) = \(\dfrac{-7}{5}\)
\(x\) = \(\dfrac{-7}{5}:2\)
\(x\) = \(\dfrac{-7}{10}\)
b, \(1\dfrac{1}{2}\) \(x\) + 75% = 1
\(\dfrac{3}{2}\) \(x\) +\(\dfrac{3}{4}\) = 1
\(\dfrac{3}{2}x\) = 1 - \(\dfrac{3}{4}\)
\(\dfrac{3}{2}x\) = \(\dfrac{1}{4}\)
\(x\) = \(\dfrac{1}{4}:\dfrac{3}{2}\)
\(x\) = \(\dfrac{1}{12}\)
Câu 3:
Bài giải:
Đổi 30% = 30/100
Tổng số bài loại giỏi và loại khá chiếm :
3/10 + 2/3 = 29/30 (bài)
Vì không có bài yếu kém, nên số bài loại trung bình chiếm: (font bị lỗi nhé)
1 - 29/30 = 1/30 (bài)
Mà có 24 bài là TB
Vậy số HS khối 6 là :
24 . 30 = 720 (HS)
Đ/S: 720 HS
Bài 1:
a: C
b: C
Bài 2:
a: D
b: 3h15p chiều=15h15p phút
7 giờ kém 10 phút=6h50p
Quãng thời gian từ 6h50 đến 15h15 là:
15h15p-6h50p=14h75p-6h50p=8h25p
X:0,1+Xx3/4-Xx50%=1025
Xx10+Xx0,75+-Xx0,5=1025
Xx(10+0,75-0,5)=1025
X x 10,25=1025
X=1025:10,25
X=100
5 Because of the noisy construction site, they couldn't concentrate on their work
6 Because of the difficult test, I couldn't do it
7 Although the prices are high, my daughters insist on going to the movie
8 Because of her mother's illness, she stayed at home
9 Despite being hungry, she didn't eat much
10 Because of having behaved badly, he must be punished
5. Because of the noisy constructionsite, they couldn't concentrate on their work.
6. Because of the test's difficulty, I couldn't do it.
7. Although the prices are high, my daughters insist on going to the movie.
8. Because of her sick mother/mother's sickness, she stayed at home.
9. Despite being hungry, she didn't eat anything.
10. Because of his bad behaviour, he must be punished.
SAU SỐ GIỜ 2 Ô TÔ GẶP NHAU LÀ :
276:(42+50)=3 (GIỜ)
ĐÁP SỐ : 3 GIỜ
\(1\dfrac{5}{7}\) x \(\dfrac{3}{4}-\dfrac{2}{7}\) 10 - 2,4 x 1,8
= \(\dfrac{12}{7}\) x \(\dfrac{3}{4}-\dfrac{2}{7}\) = 10 - 4,32
= \(\dfrac{3}{7}\) x 3 - \(\dfrac{3}{7}\) = 5,68
= \(\dfrac{9}{7}-\dfrac{3}{7}=\dfrac{6}{7}\)
Lời giải:
$1\frac{5}{7}\times \frac{3}{4}-\frac{2}{7}=\frac{12}{7}\times \frac{3}{4}-\frac{2}{7}$
$=\frac{9}{7}-\frac{2}{7}=\frac{7}{7}=1$
--------------------
$10-2,4\times 1,8=10-4,32=5,68$
tỉ số phần trăm giữa 12 và 50 là :
12:50=0,24
0,24=24%
Tỉ số % của 12 và 50 là:
12 : 50 x 100 = 24%
Đ/S:24%